如何使用wpdb插入数据

时间:2013-08-07 06:53:38

标签: php wordpress wpdb

我写的如下

$name="Kumkum";
$email="kumkum@gmail.com";
$phone="3456734567";
$country="India";
$course="Database";
$message="hello i want to read db";
$now = new DateTime();
$datesent=$now->format('Y-m-d H:i:s');    
global $wpdb;
$sql = $wpdb->prepare(
 "INSERT INTO `wp_submitted_form`      (`name`,`email`,`phone`,`country`,`course`,`message`,`datesent`) values ("
 $name, $email, $phone, $country, $course, $message, $datesent. ')")';

$wpdb->query($sql);

它不起作用......它会引发错误......请帮助我纠正它。

8 个答案:

答案 0 :(得分:76)

使用$wpdb->insert()

$wpdb->insert('wp_submitted_form', array(
    'name' => 'Kumkum',
    'email' => 'kumkum@gmail.com',
    'phone' => '3456734567', // ... and so on
));

答案 1 :(得分:16)

只需使用wpdb->insert(tablename, coloumn, format),wp即可准备该查询

<?php
global $wpdb;
$wpdb->insert("wp_submitted_form", array(
   "name" => $name,
   "email" => $email,
   "phone" => $phone,
   "country" => $country,
   "course" => $course,
   "message" => $message,
   "datesent" => $now ,
));
?>

答案 2 :(得分:4)

您必须正确检查quotes

$sql = $wpdb->prepare(
    "INSERT INTO `wp_submitted_form`      
       (`name`,`email`,`phone`,`country`,`course`,`message`,`datesent`) 
 values ($name, $email, $phone, $country, $course, $message, $datesent)");
$wpdb->query($sql);

你可以使用like,

$sql = "INSERT INTO `wp_submitted_form`
          (`name`,`email`,`phone`,`country`,`course`,`message`,`datesent`) 
   values ($name, $email, $phone, $country, $course, $message, $datesent)";

$wpdb->query($sql);

阅读http://codex.wordpress.org/Class_Reference/wpdb

答案 3 :(得分:3)

试试这个

我最近倾向于关注$wpdb->prepare HERE并添加到我们的免费课程预订插件中,插件已在wordpress.org上获得批准并将很快上线:

global $wpdb;
$tablename = $wpdb->prefix . "submitted_form";

$name     = "Kumkum"; //string value use: %s
$email    = "kumkum@gmail.com"; //string value use: %s
$phone    = "3456734567"; //numeric value use: %d
$country  = "India"; //string value use: %s
$course   = "Database"; //string value use: %s
$message  = "hello i want to read db"; //string value use: %s
$now      = new DateTime(); //string value use: %s
$datesent = $now->format('Y-m-d H:i:s'); //string value use: %s

$sql = $wpdb->prepare("INSERT INTO `$tablename` (`name`, `email`, `phone`, `country`, `course`, `message`, `datesent`) values (%s, %s, %d, %s, %s, %s, %s)", $name, $email, $phone, $country, $course, $message, $datesent);

$wpdb->query($sql);

由于 -Frank

答案 4 :(得分:1)

SQL 中的问题:

你可以像这样构建你的SQL:

$wpdb->prepare(
 "INSERT INTO `wp_submitted_form` 
   (`name`,`email`,`phone`,`country`,`course`,`message`,`datesent`) 
   values ('$name', '$email', '$phone', '$country', 
         '$course', '$message', '$datesent')"
 );

您也可以使用$wpdb->insert()

$wpdb->insert('table_name', input_array())

答案 5 :(得分:1)

推荐的方式(如in codex所述):

$wpdb->insert( $table_name, array('column_name_1'=>'hello', 'other'=> 123), array( '%s', '%d' ) );

因此,您最好清理价值-始终考虑安全性。

答案 6 :(得分:0)

global $wpdb;
$insert = $wpdb->query("INSERT INTO `front-post`(`id`, `content`) VALUES ('$id', '$content')");

答案 7 :(得分:-5)

$wpdb->query("insert into ".$table_name." (name, email, country, country, course, message, datesent) values ('$name','$email', '$phone', '$country', '$course', '$message', )");