我编写了一个查询来编辑与ID相关的特定ROW。我正在使用UPDATEALL()函数来更新我的记录。
这是CakePHP中使用的一般语法,我也在下面使用相同的语法
$this->Ticket->updateAll(
array('Ticket.status' => "'closed'"),
array('Ticket.customer_id' => 453)
);
我的代码看起来像这样。
$this->Invoicecustomers->updateAll(
array(
'user_id'=> $_GET['user_id'],
'inv_id' => $_GET['inv_id']
),array(
'Invoicecustomers.user_id'=> $_GET['user_id'],
'Invoicecustomers.inv_id' => $_GET['inv_id'])
);
$_GET['user_id']
&从网址中提取$_GET['inv_id']
当我运行编辑功能时,它会抛出一个错误。
当回应$_GET['user_id']
& $_GET['inv_id']
,结果不是空的。所以我在这里发送任何空数据。
我对这样传递的值得到了完美的回应:
$this->loadModel('Invoicecustomer');
$cust = $this->Invoicecustomer->find('all',array(
'conditions' => array('Invoicecustomer.inv_id' => $_GET['inv_id'])
));
/*$log = $this->Invoicecustomer->getDataSource()->getLog(false, false);
debug($log);*/
echo "we are getting User_id as <strong>".$cust[0]['Invoicecustomer']['user_id'] . "</strong> and inv_id as <strong>". $cust[0]['Invoicecustomer']['inv_id']."</strong>";
确保这是我为上述查询打印数组时得到的结果
Array
(
[0] => Array
(
[Invoicecustomer] => Array
(
[id] => 34
[user_id] => abc
[group_id] => 346027119
[address1] => Corte Madera
[address2] => CA
[address3] => 94925
[comment] => invoice default comment
[cust_name] => Daniel Higgins
[date1] => 2013-08-06 19:41:11
[email] => d-higgins@mac.com
[inv_id] => 1030
[tax_include] => NO
[tax_rate] => 5.00
[datastatus] => Admin
[mobile] => 555-478-7672
[sentstatus] => Not Sent
[status] => Unpaid
[street] => 332 Laguna Street
[paidamount] => 0.00
[balanceamount] => 0.00
[voidstatus] => unpaid
[signature] => nitin236090907.jpg
[imagepath] => http://192.168.1.100/cakephp_new/app/webroot/img/Invoicecustomer/346027119/abc/
)
)
)
这是我的错误屏幕
Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use
SQL Query:
UPDATE `cakephpdb`.`invoicecustomers` AS `Invoicecustomer` SET `Invoicecustomer`.`user_id` = nitin, `Invoicecustomer`.`group_id` = 346027119, `Invoicecustomer`.`address1` = Atlanta, `Invoicecustomer`.`address2` = GA, `Invoicecustomer`.`address3` = 30303, `Invoicecustomer`.`comment` = invoice default comment, `Invoicecustomer`.`cust_name` = nitin ksagar13, `Invoicecustomer`.`email` = John-Appleseed@mac.com, `Invoicecustomer`.`inv_id` = 1030, `Invoicecustomer`.`tax_include` = NO, `Invoicecustomer`.`tax_rate` = 5.00, `Invoicecustomer`.`datastatus` = Admin, `Invoicecustomer`.`mobile` = 888-555-5512, `Invoicecustomer`.`sentstatus` = Not Sent, `Invoicecustomer`.`status` = Unpaid, `Invoicecustomer`.`street` = 3494 Kuhl Avenue, `Invoicecustomer`.`paidamount` = 0.00, `Invoicecustomer`.`balanceamount` = 0.00, `Invoicecustomer`.`voidstatus` = unpaid, `Invoicecustomer`.`signature` = nitin885659375.jpg, `Invoicecustomer`.`imagepath` = http://192.168.1.100/cakephp_new/app/webroot/img/Invoicecustomer/346027119/nitin/ WHERE `Invoicecustomer`.`user_id` = 'nitin' AND `Invoicecustomer`.`group_id` = '346027119' AND `Invoicecustomer`.`inv_id` = '1030'
Notice:
If you want to customize this error message, create app/View/Errors/pdo_error.ctp
Stack Trace
CORE/Cake/Model/Datasource/DboSource.php line 460 → PDOStatement->execute(array)
CORE/Cake/Model/Datasource/DboSource.php line 426 → DboSource->_execute(string, array)
CORE/Cake/Model/Datasource/Database/Mysql.php line 379 → DboSource->execute(string)
CORE/Cake/Model/Model.php line 2372 → Mysql->update(AppModel, array, null, array)
APP/Controller/InvoicecustomersController.php line 164 → Model->updateAll(array, array)
[internal function] → InvoicecustomersController->editInvoiceCustomer()
CORE/Cake/Controller/Controller.php line 486 → ReflectionMethod->invokeArgs(InvoicecustomersController, array)
CORE/Cake/Routing/Dispatcher.php line 187 → Controller->invokeAction(CakeRequest)
CORE/Cake/Routing/Dispatcher.php line 162 → Dispatcher->_invoke(InvoicecustomersController, CakeRequest, CakeResponse)
APP/webroot/index.php line 109 → Dispatcher->dispatch(CakeRequest, CakeResponse)
我的语法是否有任何错误。?
答案 0 :(得分:1)
生成的SQL似乎有一些错误,例如它包含
`Invoicecustomer`.`user_id` = nitin
虽然nitin应该在qoutes之间。如果CakePHP生成此SQL(显然它确实如此),则似乎数据库中的字段未正确定义。例如,通常user_id将是INT或bigINT),但您将其用作CHAR,在这种情况下,您的数据库模型应该与之匹配。否则,CakePHP可能会生成错误的查询,就像现在一样。
实际上,如果我是正确的,似乎所有的表列都被定义为INT,而不是您想要存储在其中的数据类型。
答案 1 :(得分:1)
Try...
$user_id = $_GET['user_id'];
$this->Invoicecustomers->updateAll(
array(
'user_id'=> "'$user_id'",
'inv_id' => $_GET['inv_id']
),array(
'Invoicecustomers.user_id'=> "'$user_id'",
'Invoicecustomers.inv_id' => $_GET['inv_id'])
);