我需要使用代码使翻转图像在其下方(文本)创建下拉列表,并在鼠标悬停在下拉列表中或原始图像上时返回原始图像。
任何人都有代码来完成此任务吗?我整天都在改变这个网站的代码,并且非常接近并不完全在那里。
菜单
<table width="830px" border=0 cellspacing=0 cellpadding=0 >
<tr height="25px">
<td valign="top" align="left"><a href="aboutus1.php"><img src="images/cti-logo.png"></a></td>
<td valign="bottom" align="right"><a href="welcome.php">
<img src="images/home.jpg" onMouseOver="this.src='images/hover-home.jpg'" onMouseOut="this.src='images/home.jpg'"/>
<a href="aboutus1.php" target="content"><img id="id_About" onClick="over('about')" src="images/aboutus.jpg" onmouseover="this.src='images/hover-aboutus.jpg'" onMouseOut="if(me2=='about'){}else{this.src='images/aboutus.jpg'}" /></a>
<a target="content" href="partners.php" ><img onClick="over('partners')" id="id_Partners" src="images/partners.jpg" onMouseOver="this.src='images/hover-partners.jpg'" onMouseOut="if(me2=='partners'){}else{this.src='images/partners.jpg'}" /></a>
<a href="products1_1.php" target="content"><img onClick="over('products')" id="id_Products" src="images/products.jpg" onmouseover="this.src='images/hover-products.jpg'" onMouseOut=" if(me2=='products'){}else{this.src='images/products.jpg'}" /></a>
<a href="contactus.php" target="content"><img id="id_Contactus" onClick="over('contactus')" src="images/contactus.jpg" onmouseover="this.src='images/hover-contactus.jpg'" onMouseOut=" if(me2=='contactus'){}else{this.src='images/contactus.jpg'}" class="contactus" /></a>
</td>
</tr>
<tr>
<td colspan="2" class="bar"></td>
</tr>
</table>
答案 0 :(得分:0)
看看这个JSFiddle。希望这就是你所需要的。
http://jsfiddle.net/mohsin1303/RtMQh/
HTML代码
<html>
<head>
<title>This is a demo using CSS Sprites</title>
<style>
.myButtonLink {
display: block;
width: 100px;
height: 100px;
background: url('http://www.justcode.us/wp-content/uploads/2013/04/buttonleafhover.png') bottom;
}
.myButtonLink:hover {
background-position: 0 0;
}
</style>
</head>
<body>
<a class="myButtonLink" href="#LinkURL"></a>
</body>
</html>