我的数据以格式存储(向下看):[ - ]表示空白单元格, 在空间之后,右边可能只有10列。像这样:
[string0] [-] [string1] [string2] [string3] .. [string10] [-]
如何更改此代码:
获取完整字符串,对于每一行fullString = [ - ] [string1] [string2] [string3] .. [string10] [ - ]。 StringBuilder的?或者怎么样?
//Get first sheet from the workbook
HSSFSheet sheet = workbook.getSheetAt(0);
//Iterate through each rows from first sheet
Iterator<Row> rowIterator = sheet.iterator();
while(rowIterator.hasNext()) {
Row row = rowIterator.next();
//For each row, iterate through each columns
Iterator<Cell> cellIterator = row.cellIterator();
while(cellIterator.hasNext()) {
Cell cell = cellIterator.next();
switch(cell.getCellType()) {
case Cell.CELL_TYPE_STRING:
System.out.print(cell.getStringCellValue() + "\t\t");
list1.add(cell.getStringCellValue());
break;
}
}
System.out.println("");
}
file.close();
FileOutputStream out =
new FileOutputStream("C:\\Users\\student3\\"+sfilename+".xls");
workbook.write(out);
out.close();
答案 0 :(得分:0)
外部链接:Busy Developers' Guide to HSSF and XSSF Features
这是一个应该有效的例子。
Maven依赖:
<dependency>
<groupId>org.apache.poi</groupId>
<artifactId>poi</artifactId>
<version>3.9</version>
</dependency>
<dependency>
<groupId>org.apache.poi</groupId>
<artifactId>poi-ooxml</artifactId>
<version>3.9</version>
</dependency>
代码:
import org.apache.poi.hssf.usermodel.HSSFDataFormatter;
import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
import org.apache.poi.ss.usermodel.*;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.Iterator;
public class StackOverflowQuestion18095443 {
public static void main(String[] args) {
if(args.length != 1) {
System.out.println("Please specify the file name as a parameter");
System.exit(-1);
}
String sfilename = args[0];
File file = new File("C:\\Users\\student3\\" + sfilename + ".xls");
read(file);
}
public static void read(File file) {
try (InputStream in = new FileInputStream(file)) {
HSSFDataFormatter formatter = new HSSFDataFormatter();
Workbook workbook = WorkbookFactory.create(in);
Sheet sheet = workbook.getSheetAt(0);
Iterator<Row> rowIterator = sheet.iterator();
while (rowIterator.hasNext()) {
Row row = rowIterator.next();
StringBuilder rowText = new StringBuilder();
Iterator<Cell> cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
Cell cell = cellIterator.next();
String cellAsStringValue = formatter.formatCellValue(cell);
rowText.append(cellAsStringValue).append(" ");
}
System.out.println(rowText.toString().trim());
}
} catch (InvalidFormatException | IOException e) {
e.printStackTrace();
}
}
}