Question

我正在使用hibernate和oracle DB尝试使用序列将自动ID插入表中。该序列肯定存在于数据库中，但是hibernate似乎无法找到它。

以下是所有相关信息：

SLF4J: Failed to load class "org.slf4j.impl.StaticLoggerBinder".
SLF4J: Defaulting to no-operation (NOP) logger implementation
SLF4J: See http://www.slf4j.org/codes.html#StaticLoggerBinder for further details.
org.hibernate.exception.SQLGrammarException: could not get next sequence value
    at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:92)
    at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)
        ....
Caused by: java.sql.SQLSyntaxErrorException: ORA-02289: sequence does not exist
        ....
    ... 12 more

我知道它说“引起：java.sql.SQLSyntaxErrorException：ORA-02289：序列不存在”但我可以访问数据库上的序列：

表：

CREATE TABLE Property(
  id INT,
  address VARCHAR2(50),
  town VARCHAR2(50),
    postCode VARCHAR2(50),
    purchasePrice INT
);

序列：

create sequence property_seq start with 1 increment by 1 nomaxvalue;

映射xml：

<class name="com.rental.model.property.Property" table="PROPERTY">
    <meta attribute="class-description"> This class contains the property detail. </meta>
    <id name="id" type="integer" column="id">
        <generator class="sequence"/>
    </id>
    <property name="address" column="ADDRESS" type="string" />
    <property name="town" column="TOWN" type="string" />
    <property name="postCode" column="POSTCODE" type="string" />
    <property name="purchasePrice" column="PURCHASEPRICE" type="integer" />
</class>

注释：

@Id
@SequenceGenerator(name="property_seq", sequenceName="property_seq", allocationSize=1, initialValue=1) 
@GeneratedValue (strategy = GenerationType.SEQUENCE, generator="property_seq")
public int getId() {
    return id;
}

Answer 1

为什么你同时使用xml AND @Annotation？也许xml定义胜过注释，而Hibernate正在重新启动默认序列，而不是property_seq 尝试删除xml映射并检查它是否有效。

Hibernate / Oracle Sequence无法正常工作

1 个答案: