Question

我在tableview中添加了UIWebview以显示文本和链接，但无法滚动tableview，任何在webview中禁用用户交互的方法都只是单击事件启用。

Webview的静态内容无法从网络加载

NSString * htmlString = [NSString stringWithFormat:@"<html><head><script> document.ontouchmove = function(event) { if (document.body.scrollHeight == document.body.clientHeight) event.preventDefault(); } </script><style type='text/css'>* { margin:0; padding:0;} p { color:white; font-family:HelveticaNeue-CondensedBold; font-size:24px;} a { color:#63B604; text-decoration:underline; }</style></head><body><p>%@</p></body></html>", @"search in http://google.com"];

由于

Answer 1

只是禁用滚动或使用此方法

- (void)webViewDidFinishLoad:(UIWebView *)webView {
    // Disable user selection
    [webView stringByEvaluatingJavaScriptFromString:@"document.documentElement.style.webkitUserSelect='none';"];
    // Disable callout
    [webView stringByEvaluatingJavaScriptFromString:@"document.documentElement.style.webkitTouchCallout='none';"];
}

使用delagate方法打开如下链接

-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
    if ( inType == UIWebViewNavigationTypeLinkClicked ) {
        NSURL *url = [inRequest URL];
        if ([[url absoluteString] rangeOfString:@"gmail"].location == NSNotFound) {
            [[UIApplication sharedApplication] openURL:[inRequest URL]];
            return NO;
        }
    }
    return YES;
}

Answer 2

我从网站上得到了答案 http://nickharris.wordpress.com/2010/06/17/fast-uitableviewcell-with-a-uiwebview/

Answer 3

尝试在WebView中禁用滚动

[myWebView.scrollView setScrollEnabled:NO]; 
[myWebView.scrollView setBounces:NO];

在UIWebView上禁用交互，只能链接可点击？

3 个答案: