Question

URL_COMPONENTS urlComp;
LPCWSTR pwszUrl1 = 
  L"http://search.msn.com/results.asp?RS=CHECKED&FORM=MSNH&v=1&q=wininet";
DWORD dwUrlLen = 0;

// Initialize the URL_COMPONENTS structure.
ZeroMemory(&urlComp, sizeof(urlComp));
urlComp.dwStructSize = sizeof(urlComp);

// Set required component lengths to non-zero 
// so that they are cracked.
urlComp.dwSchemeLength    = (DWORD)-1;
urlComp.dwHostNameLength  = (DWORD)-1;
urlComp.dwUrlPathLength   = (DWORD)-1;
urlComp.dwExtraInfoLength = (DWORD)-1;

// Crack the URL.
if (!WinHttpCrackUrl( pwszUrl1, (DWORD)wcslen(pwszUrl1), 0, &urlComp))
{
    printf("Error %u in WinHttpCrackUrl.\n", GetLastError());
}

这个WinHttpCrackUrl api在Win7（OS）上失败了87（无效参数）请任何人建议解决方案或如何在服务器端轻松解码我的URL？。我也想知道如何区分％ 20来自URL中的编码URL和实际数据。示例：localhost：8080 \ Server \ search？value =“value％20”

Answer 1

将所需的组件长度设置为预期值。

如果不需要破解，则全部为零。

urlComp.dwSchemeLength    = (DWORD)0;
urlComp.dwHostNameLength  = (DWORD)0;
urlComp.dwUrlPathLength   = (DWORD)0;
urlComp.dwExtraInfoLength = (DWORD)0;

或

std::wstring urlHost;
urlHost.resize(url.size());

urlComp.dwHostNameLength = (DWORD)urlHost.size();
urlComp.lpszHostName = &urlHost[0];

WinHttpCrackUrl失败，出现87错误

1 个答案: