Question

我将我的XMLString映射到XMLSchema，如下面的代码（我正在使用任何元素的Schema）：

XmlReaderSettings settings = new XmlReaderSettings();
settings.DtdProcessing = DtdProcessing.Parse;
settings.ValidationType = ValidationType.Schema;
settings.ValidationFlags |= XmlSchemaValidationFlags.ProcessInlineSchema;
settings.ValidationFlags |= XmlSchemaValidationFlags.AllowXmlAttributes;
settings.ValidationFlags |= XmlSchemaValidationFlags.ReportValidationWarnings;

settings.Schemas.Add(null, XmlReader.Create(new StringReader(@"<xs:schema  xmlns:xs=""http://www.w3.org/2001/XMLSchema"">
                                                    <xs:element name=""bpElements"">
                                                    <xs:complexType>
                                                    <xs:sequence>
                                                     <xs:any />
                                                    </xs:sequence>
                                                   </xs:complexType>
                                                </xs:element>
                                             </xs:schema>")));

try
{
    // Create the XmlReader object.
    XmlReader xmlrdr = XmlReader.Create(new StringReader("<root>" + ab + "</root>"), settings);
    // Parse the file. 
    while (xmlrdr.Read()) ;
}
catch (XmlSchemaValidationException ex)
{
    Console.WriteLine("The file could not read the value at XML  format is not correct due to" + ex);
}

1）异常我的Root Element缺失。

为了避免上述错误：当我将根元素添加到我的架构时：
（参考：Is it possible to define a root element in an XML Document using Schema?）

settings.Schemas.Add(null, XmlReader.Create(new StringReader(@"<xs:schema  xmlns:xs=""http://www.w3.org/2001/XMLSchema"">
                                                            <xs:element name=""root"" type=""RootElementType""/>
                                                            <xs:complexType name=""RootElementType"">
                                                            <xs:sequence>
                                                             <xs:any />
                                                            </xs:sequence>
                                                           </xs:complexType>
                                                        </xs:element>
                                                     </xs:schema>")));

会抛出错误：

The 'xs:schema' start tag on line 1 position 2 does not match the end tag of 'xs:element'. Line 8, position 63.

请告诉我如何解决这个问题。

Answer 1

从字符串

中删除</xs:element>

继承人更新代码

    settings.Schemas.Add(null, XmlReader.Create(
    new StringReader(@"<xs:schema  xmlns:xs=""http://www.w3.org/2001/XMLSchema"">
                        <xs:element name=""root"" type=""RootElementType""/>
                        <xs:complexType name=""RootElementType"">
                        <xs:sequence>
                         <xs:any />
                        </xs:sequence>
                       </xs:complexType>
                 </xs:schema>")));

访问XMLSchema中的Root元素

1 个答案: