Question

以下SQL抛出错误8120，其中说：

列'webgroup_message2_archive.opened'在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中

即使我没有使用违规列作为SELECT子句的一部分。当我更改子查询

时

SELECT webgroup_message2_testTable.message_id

到一个像（111,222，...等）的列表`它有效！所以问题来自子查询与聚合函数不兼容？我还确保子查询的数据类型与测试表达式匹配。

SELECT 
  CASE
      WHEN arch.opened = '1' 
      THEN(CASE 
             WHEN (message_id IN (SELECT webgroup_message2_testTable.message_id 
                                  FROM webgroup_message2_testTable)) 
             THEN 'Clicked' ELSE 'Opened' END)
      ELSE 'No activity/response'
  END AS status, count(1)
FROM webgroup_message2_archive AS arch
INNER JOIN webgroup_development AS dev
      ON dev.development_id = arch.HTMLID
WHERE dev.email_tracker_code = 'A4725'
GROUP BY 
  CASE
      WHEN arch.opened= '1' 
      THEN( CASE 
             WHEN (message_id IN (SELECT webgroup_message2_testTable.message_id 
                                  FROM webgroup_message2_testTable)) 
             THEN 'Clicked' ELSE 'Opened' END)
      ELSE 'No activity/response'
  END

Answer 1

我认为您不能在group by子句中使用子查询。您可以使用left join查看邮件是否可用来执行相同的操作。

SELECT (CASE WHEN arch.opened= '1' 
             THEN (CASE WHEN ttmessage_id is not null 
                        THEN 'Clicked'
                        ELSE 'Opened'
                   END)
             ELSE 'No activity/response'
        END), count(1)
FROM webgroup_message2_archive arch INNER JOIN
     webgroup_development AS dev
     ON dev.development_id = arch.HTMLID left outer join
     (select distinct tt.message_id as ttmessage_id
      from webgroup_message2_testTable tt
     ) tt
     on message_id = tt.ttmessage_id
WHERE dev.email_tracker_code = 'A4725'
GROUP BY (CASE WHEN arch.opened= '1' 
               THEN (CASE WHEN ttmessage_id is not null 
                          THEN 'Clicked'
                          ELSE 'Opened'
                     END)
               ELSE 'No activity/response'
          END)

Answer 2

如果您尝试按状态获取邮件计数，则可以使用左连接并删除子查询。类似于戈登的答案，几分钟击败我，但外观略有不同。这仅在您的意图有效时才有效。

SELECT 
  CASE
      WHEN arch.opened = '1' 
      THEN (CASE WHEN test.message_id IS NOT NULL THEN 'Clicked' ELSE 'Opened' END)
      ELSE 'No activity/response'
  END AS status, 
  count(distinct(arch.message_id))
FROM webgroup_message2_archive AS arch
INNER JOIN webgroup_development AS dev
      ON dev.development_id = arch.HTMLID
LEFT JOIN webgroup_message2_testTable AS test
      ON arch.message_id = test.message_id
WHERE dev.email_tracker_code = 'A4725'
GROUP BY 
  CASE
      WHEN arch.opened = '1' 
      THEN (CASE WHEN test.message_id IS NOT NULL THEN 'Clicked' ELSE 'Opened' END)
      ELSE 'No activity/response'
  END

不确定arch.message_id是否正确或者是否应该是dev.message_id。您应该总是尝试使用表/别名来为列名添加前缀，这样就不会有关于列来自何处的任何问题。

Microsoft SQL Server错误

2 个答案: