Question

有没有更好的方法将scala JsValue（或JsArray）转换为java ObjectNode？

Scala的：

object Event {
    def getEventsJson(id: String, limit: Int): Option[JsArray] = {
        val list = getEvents(id, limit)
        val buffer = new scala.collection.mutable.ListBuffer[JsValue]
        list.foreach(e => buffer += Json.toJson(e))
        Json.toJson(buffer.toList) match {
          case x: JsArray => Some(x)
          case _ => None
        }
    }
}

爪哇：

ObjectNode result = Json.newObject();
Option<JsArray> eventsOpt = Event.getEventsJson(id, 3);
if (eventsOpt.isDefined()) {
   result.put("events", play.libs.Json.parse(play.api.libs.json.Json.stringify(eventsOpt.get())));
}

**编辑基于@Freidereikhs评论的更改

object Event {
  def getEventsJson(convoId: String, limit: Int): Option[JsArray] = {
    val jsonEvents = getEvents(convoId, limit).map(e => Json.toJson(e))
    Json.toJson(jsonEvents) match {
      case x: JsArray => Some(x)
      case _ => None
    }
  }
}

Answer 1

我认为你可以通过替换

来改善这一点

val list = getEvents(id, limit)
val buffer = new scala.collection.mutable.ListBuffer[JsValue]
list.foreach(e => buffer += Json.toJson(e))

与

val jsonEvents = getEvents.map(e => Json.toJson(e))

播放2.1 Scala JsValue到Java ObjectNode

1 个答案: