我有两个按钮的警报视图,但按钮不会打开网址。我不知道错误。请帮助。
以下是代码:
-(IBAction)showAlertView {
UIAlertView *alert = [[UIAlertView alloc]
initWithTitle:@"Obrir en..."
message:@"Es pot requirir la aplicació de Google Maps"
delegate:self
cancelButtonTitle:@"Millor no..."
otherButtonTitles:@"Mapes",@"Google Maps",nil];
[alert show];
}
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
NSString *title = [alertView buttonTitleAtIndex:buttonIndex];
if([title isEqualToString:@"Mapes"])
{
UIApplication *ourApplication = [UIApplication sharedApplication];
NSString *ourPath = @"http://maps.apple.com/?q=Plaça+del+Rei+43003+Tarragona";
NSURL *ourURL = [NSURL URLWithString:ourPath];
[ourApplication openURL:ourURL];
}
if([title isEqualToString:@"Google Maps"])
{
UIApplication *ourApplication = [UIApplication sharedApplication];
NSString *ourPath = @"comgooglemaps://?daddr=Plaça+del+Rei+43003+Tarragona&directionsmode=walking";
NSURL *ourURL = [NSURL URLWithString:ourPath];
[ourApplication openURL:ourURL];
}
}
答案 0 :(得分:5)
我认为地址中的特殊字符(ç)会关闭NSURL。在将其传递给NSURL初始化程序之前,请尝试使用NSString的stringByAddingPercentEscapesUsingEncoding:
方法对其进行编码。
答案 1 :(得分:1)
请检查我们解雇的网址。
if([ourApplication canOpenURL:ourURL])
[ourApplication openURL:ourURL];
else
NSLog(@"URL is not valid.");
当我检查两个网址时,他们无法打开。 您可以使用上面的代码检查URL,无论URL是否能够打开。
答案 2 :(得分:1)
你必须检查网址,试试这个:
-(IBAction)showAlertView {
UIAlertView *alert = [[UIAlertView alloc]
initWithTitle:@"Obrir en..."
message:@"Es pot requirir la aplicació de Google Maps"
delegate:self
cancelButtonTitle:@"Millor no..."
otherButtonTitles:@"Mapes",@"Google Maps",nil];
[alert show];
}
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
//0 is cancel
if(buttonIndex == 1)
{
[self openURLWithString:@"https://www.google.com/maps/preview#!q=Pla%C3%A7a+del+Rei+43003+Tarragona&data=!1m4!1m3!1d4618!2d1.2582895!3d41.1168719!4m11!1m10!4m8!1m3!1d26081603!2d-95.677068!3d37.0625!3m2!1i1024!2i768!4f13.1!17b1"];
}
if(buttonIndex == 2)
{
[self openURLWithString:@"https://www.google.com/maps/preview#!data=!1m4!1m3!1d18473!2d1.258181!3d41.1168316!4m13!3m12!1m0!1m1!1sPla%C3%A7a+del+Rei+43003+Tarragona!3m8!1m3!1d26081603!2d-95.677068!3d37.0625!3m2!1i1024!2i768!4f13.1&fid=0"];
}
}
- (void)openURLWithString:(NSString *)string{
UIApplication *ourApplication = [UIApplication sharedApplication];
NSString *ourPath = string;
NSURL *ourURL = [NSURL URLWithString:ourPath];
if([ourApplication canOpenURL:ourURL])
[ourApplication openURL:ourURL];
else
NSLog(@"URL is not valid.");
}
答案 3 :(得分:0)
首先,您应该在第二个条件中使用elseif
,因为如果第一个不是真的,您只想要触发第二个条件。其次,它似乎是您在@“Mapes”中使用的URL ...我测试了这个并且该URL似乎是罪魁祸首。当我将该URL更改为另一个测试URL时,它可以正常工作。