这是对Concurrency
上的Java教程的代码的修改package threads;
public class SimpleThreads {
static void threadMessage(String msg) {
String threadName = Thread.currentThread().getName();
System.out.format("%s: %s%n", threadName,msg);
}
private static class MessageLoop implements Runnable{
@Override
public void run() {
// TODO Auto-generated method stub
String[] importantInfo= {"apple","bat","chlorine","dog","egg","fog","gun"};
try {
for(int i=0;i<importantInfo.length;i++) {
Thread.sleep(4000);
threadMessage(importantInfo[i]);
}
}catch(InterruptedException ie) {
threadMessage("i wasn't done");
}
}
}
/**
* @param args
*/
public static void main(String[] args) throws InterruptedException{
// TODO Auto-generated method stub
long patience = 100;
if(args.length > 0)
try {
patience = Long.parseLong(args[0]) * 1000;
}catch(NumberFormatException nfe) {
System.err.println("argument must be a integer");
System.exit(1);
}
threadMessage("starting message loop thread");
long startTime = System.currentTimeMillis();
Thread t = new Thread(new MessageLoop());
t.start();
threadMessage("waiting for messageloop thread to finish");
while(t.isAlive()) {
threadMessage("still waiting...");
//t.join(1000);
if(((System.currentTimeMillis() - startTime) > patience) && t.isAlive()) {
threadMessage("tired of waiting");
t.interrupt();
//t.join();
}
}
threadMessage("finally");
}
}
这是输出
main: starting message loop thread
main: waiting for messageloop thread to finish
main: still waiting...
main: still waiting...
...(repeats about 100 times)
main: still waiting...
main: still waiting...
main: still waiting...
main: still waiting...
main: tired of waiting
main: still waiting...
main: tired of waiting
main: still waiting...
main: tired of waiting
main: still waiting...
main: tired of waiting
main: still waiting...
main: tired of waiting
Thread-0: i wasn't done
main: finally
我预计在第一次(并且据说只有)main: tired of waiting
之后,我会看到Thread-0: i wasn't done
,但main: tired of waiting
会出现5次 - 为什么会这样?
答案 0 :(得分:5)
Thread.Interrupt()只是向目标线程发送一个中断(信号/异常);它不会立即杀死它。
此外,在发送中断与目标线程接收和处理中断之间可能存在延迟;不保证上下文切换是立即的。
您可以通过执行某种形式的阻塞操作(例如I / O或休眠)或通过调用Thread.yield()来鼓励(但不强制)JVM更快地进行上下文切换。
答案 1 :(得分:0)
Thread.interrupt()
不会杀死或中断线程
它只会中断某些方法,如睡眠,等待,加入,可中断通道上的阻塞I / O或阻塞的选择器。否则它只是设置线程的中断标志,由你来测试这个标志
如果你在上面的代码中删除了睡眠,那么中断将没有明显的效果。
线程将(可能)被中断几次,因为实际的线程(主循环)继续运行,直到系统变为中断的线程。中断后你可以添加一个sleep()或yield()(join(),如图所示,也应该工作)以允许中断的线程运行
threadMessage("tired of waiting");
t.interrupt();
t.yield();