Question

我有一个父视图控制器和两个容器，如下所示：

UIStoryboard* storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];
MyCombinationsViewController *myComb = [storyboard instantiateViewControllerWithIdentifier:@"MyCombinationsViewControllerID"];
myComb.view.frame = self.combinationsContainer.bounds;
[self.combinationsContainer addSubview:myComb.view];
[self addChildViewController:myComb];
[myComb didMoveToParentViewController:self];

StatInfoViewController *stat = [storyboard instantiateViewControllerWithIdentifier:@"StatInfoViewControllerID"];
stat.view.frame = self.statContainer.bounds;
[self.statContainer addSubview:stat.view];
[self addChildViewController:stat];
[stat didMoveToParentViewController:self];

我想在StatInfoViewController内做一些影响MyCombinationsViewController的事情。如何在不重新分配的情况下访问MyCombinationsViewController属性？

这样做：

UIStoryboard* storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];
MyCombinationsViewController *myComb = [storyboard instantiateViewControllerWithIdentifier:@"MyCombinationsViewControllerID"];

当我尝试执行StatInfoViewController

之类的操作时，{p}内的{p>会返回空属性

Answer 1

你可以在StatInfoViewController add：

的标题中链接它们togehter

@property (nonatomic, weak) MyCombinationsViewController* myCombinationsViewController

然后在分配它们时，请执行以下操作：

StatInfoViewController *stat = [storyboard instantiateViewControllerWithIdentifier:@"StatInfoViewControllerID"];
UIStoryboard* storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];
MyCombinationsViewController *myComb = [storyboard instantiateViewControllerWithIdentifier:@"MyCombinationsViewControllerID"];

stat.myCombinationsViewController = myComb;


myComb.view.frame = self.combinationsContainer.bounds;
[self.combinationsContainer addSubview:myComb.view];
[self addChildViewController:myComb];
[myComb didMoveToParentViewController:self];

stat.view.frame = self.statContainer.bounds;
[self.statContainer addSubview:stat.view];
[self addChildViewController:stat];
[stat didMoveToParentViewController:self];

然后你可以从StatInfoViewController里面访问myCombinationsViewController

从另一个Container视图控制器访问Container视图控制器

1 个答案: