OSError:[Errno 22] python3套接字中的参数无效

时间:2013-08-04 09:58:10

标签: python sockets python-3.x pyqt4

我在Python 3中遇到套接字编程问题。我得到一个异常,它不会导致程序崩溃,但只是在终端中显示。

这是我的代码:

from PyQt4 import QtCore, QtGui
from imigui import Ui_MainWindow

class imiserv(QtGui.QMainWindow):

    send_msg = pyqtSignal('QString', 'QString')

    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.ui = Ui_MainWindow()
        self.ui.setupUi(self)
        self.ui.Sport_lineEdit.setMaxLength(5)
        self.ui.Sconnect_pushButton.clicked.connect(self.serv)

        self.send_msg.connect(self.write_msg)

    def write_msg(self, lbl_msg= None, txt_msg= None):
        if lbl_msg:
            self.ui.C_label.setText(lbl_msg)
        if txt_msg:
            self.ui.Clog_textEdit.setText(txt_msg)

    def serv(self):
        MY_LOCK = threading.Lock()
        class CountT(threading.Thread):
            def __init__(self, parent):
                threading.Thread.__init__(self)
                self._parent= parent

            def run(self):
                MY_LOCK.acquire()
                self._parent.send_msg.emit("Waiting connections","")
                while True:
                    cliconn, (addr, remoport)= self._parent.clis.accept()
                    clirecmsg= str(cliconn.recv(1024)
                    self._parent.send_msg.emit("{0}:{1} is connected.".format(addr, remoport), "{0}:{1}".format(addr, remoport)
                    cliconn.close()

                MY_LOCK.release()

        try:
            self.clis= socket.socket(socket.AF_INET, socket.SOCK_STREAM)
            self.clis.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
            clierhost= str(self.ui.Sip_lineEdit.text())
            clierport= int(self.ui.Sport_lineEdit.text())
            self.clis.bind((clierhost, clierport))
            self.clis.listen(5)
            a= CountT(self)
            a.daemon= True
            a.start()
        except socket.error as err:
            err= str(err)
            print(err)

以下是发生的交叉错误(此错误仅在linux操作系统中显示):

Exception in thread Thread-1:
Traceback (most recent call last):
  File "/usr/lib/python3.3/threading.py", line 637, in _bootstrap_inner
    self.run()
  File "imiclilap.py", line 34, in run
    cliconn, (addr, remoport)= self._parent.clis.accept()
  File "/usr/lib/python3.3/socket.py", line 135, in accept
    fd, addr = self._accept()
OSError: [Errno 22] Invalid argument

Exception in thread Thread-2:
Traceback (most recent call last):
  File "/usr/lib/python3.3/threading.py", line 637, in _bootstrap_inner
    self.run()
  File "imiclilap.py", line 34, in run
    cliconn, (addr, remoport)= self._parent.clis.accept()
  File "/usr/lib/python3.3/socket.py", line 135, in accept
    fd, addr = self._accept()
OSError: [Errno 22] Invalid argument

2 个答案:

答案 0 :(得分:0)

Errorno 22是被定义为“无效参数”的linux错误,因此您的地址或端口可能不是正确的类型。检查

  

地址,删除

是字符串,分别是int。

也可能您已经在另一个线程中绑定了套接字。

您可以在strace 1中运行程序,这将使您看到正在使用的套接字以及是否存在某些双重绑定。

也只是个疯子:

您的程序没有崩溃,因为该错误发生在单独的线程中,因此该线程正在崩溃,但您的主线程仍在运行。

答案 1 :(得分:0)

这是详细的答案 https://stackoverflow.com/a/30268744/8447510

简而言之:使用192.168.1.x代替127.0.0.1