Question

无法让sql在postgresql数据库中进行一些报告工作。我正在使用两个表，下面列出了相关的列：

cohead：cohead_id，cohead_number，cohead_orderdate
评论：comment_id，comment_source_id，comment_date，comment_text

可以在cohead_id = comment_source_id上加入两者，以查找与订单相关的所有评论。

当我们向订单准备服务提交拣配订单时，我们会在相关订单中插入带有“已提交”文本的注释。当我们通过订单准备服务关闭订单时，我们会为该订单插入“已开票”的评论。

我想要做的是获取一个时段中每天的列表，比如上个月，列出当天或之前提交的订单数量，但尚未开具发票一天。

我遇到了一些概念上的问题，我尝试过的连接速度很慢。

有什么想法吗？

Answer 1

截取日期'20130731'，'20130805'作为示例开始日期和结束日期，此查询将在这两个日期之间每天返回您需要的计数。您可以更改实际查询的参数。

;with cte as (
    select d::date as d
    from generate_series('20130731', '20130805', interval '1 day') as d
)
select
    cte.d,
    count(o.cohead_id) as cnt
from cte
    left outer join cohead as o on
        o.cohead_orderdate <= cte.d and
        not exists (
            select *
            from comment as c
            where
                c.comment_date <= cte.d and
                c.comment_text = 'Invoiced' and
                c.comment_source_id = o.cohead_id
        )
group by cte.d
order by cte.d

请参阅SQL FIDDLE EXAMPLE - 您可以添加/删除行并检查其是否正常。

希望有所帮助。

<强>更新：如果您想要提交日期而不是订单日期，则根本不需要查询订单表：

;with cte as (
    select d::date as d
    from generate_series('20130731', '20130805', interval '1 day') as d
), cte2 as (
    select
        c1.comment_date as submitted_date,
        c2.comment_date as invoiced_date,
        count(*) as cnt
    from comment as c1
        left outer join comment as c2 on
           c2.comment_source_id = c1.comment_source_id and
           c2.comment_text = 'Invoiced'
    where c1.comment_text = 'Submitted'
    group by c1.comment_date, c2.comment_date
)
select c1.d, sum(c2.cnt) 
from cte as c1
   left outer join cte2 as c2 on
       c2.submitted_date <= c1.d and
       (c2.invoiced_date is null or c2.invoiced_date > c1.d)
group by c1.d
order by c1.d

请参阅SQL FIDDLE更新的查询

更新2 ，因为OP说他的查询性能有问题，我试图用窗口函数编写另一个。这个想法是为所有日期计数提交类型的评论减去发票类型的评论，然后得到滚动总数。

;with cte1 as (
    select d::date as d
    from generate_series('20130731', '20130805', interval '1 day') as d
), cte2 as (
    select
        greatest('20130731', c.comment_date) as comment_date,
        c.comment_text, count(*) as cnt
    from comment as c
    where
        c.comment_text in ('Invoiced', 'Submitted') and
        c.comment_date <= '20130805'
    group by greatest('20130731', c.comment_date), c.comment_text
), cte3 as (
    select
        coalesce(cs.cnt, 0) - coalesce(ci.cnt, 0) as cnt,
        coalesce(cs.comment_date, ci.comment_date) as comment_date
    from (select * from cte2 where comment_text = 'Submitted') as cs
        full outer join (select * from cte2 where comment_text = 'Invoiced') as ci on
            cs.comment_date = ci.comment_date
)
select c1.d, sum(c3.cnt) over (order by c1.d)
from cte1 as c1
    left outer join cte3 as c3 on c3.comment_date = c1.d
order by c1.d

SQL FIDDLE

从日志表中发布Postgres日期报告

1 个答案: