Question

我以为我已经学会了足够的python来制作凯撒密码，所以我开始制作它并且我已经碰到了一堵砖墙。

这是我的代码：

phrase = raw_input("Enter text to Cipher: ")
shift = int(raw_input("Please enter shift: "))
result = ("Encrypted text is: ")

for character in phrase:
    x = ord(character)

    x = x + shift


print chr(x)

目前如果短语为'hi'且shift为1，则for循环只围绕字母i循环，而不是字母h，所以我的结果是：j

我想绕着整个单词循环，并按照变量int变量移动每个字母。

如何循环短语变量？

Answer 1

您的代码正在打印ord() 'j'的值，因为在循环结束时字符等于'i'。您应该将新字符存储到列表中，并在循环结束后加入它们然后打印。

new_strs = []
for character in phrase:
    x = ord(character)
    x = x + shift
    new_strs.append(chr(x))   #store the new shifted character to the list
    #use this if you want z to shift to 'a'
    #new_strs.append(chr(x if 97 <= x <= 122 else 96 + x % 122))
print "".join(new_strs)       #print the new string

<强>演示：

$ python so.py
Enter text to Cipher: hi
Please enter shift: 1
ij

Answer 2

将每个加密字符附加到result字符串。

phrase = raw_input("Enter text to Cipher: ")
shift = int(raw_input("Please enter shift: "))
result = ""

for character in phrase:
    x = ord(character)
    result += chr(x + shift)

print result

Answer 3

尝试：

phrase = raw_input("Enter text to Cipher: ")
shift = int(raw_input("Please enter shift: "))
result = ("Encrypted text is: ")
import sys
for character in phrase:
  x = ord(character)
  x = x + shift
  sys.stdout.write(chr(x))
  sys.stdout.flush()

使用Ord和Chr的Python Caesar密码

3 个答案: