如果未经身份验证,则阻止AngularJS Controller调用

时间:2013-08-03 06:31:18

标签: angularjs

我对路由更改进行了基本的身份验证检查,只检查是否存在SessionStorage密钥/ val。但是,我注意到如果未经身份验证的用户导航到禁止页面,其控制器包含AJAX调用,则即使禁用了禁用页面而用户被重定向到登录,AJAX调用仍会在后台进行。为了解决这个问题,我在每个控制器中添加了相同的身份验证检查。这变得有点乏味,我想知道是否有更好的方法,或者我可以在控制器的方法运行之前全局检查身份验证。这是路线变更的auth功能:

app.run(function ($rootScope, $location, authenticationService) {

    $rootScope.clearAlerts = function(){
        $rootScope.alerts = []
    }

    $rootScope.credentials = {
        username: "",
        password: ""
    };

    $rootScope.goto = function(url){
        $location.path(url);
    }

    $rootScope.authenticated = authenticationService.isLoggedIn()
    $rootScope.logOut = function () {
        authenticationService.logOut();
    }
    var publicRoutes = ['/login'];

    $rootScope.$on('$routeChangeStart', function (event, next, current) {
        $rootScope.credentials.from = $rootScope.desiredPath || '/login'
        $rootScope.authenticated = authenticationService.isLoggedIn();
        if (!_(publicRoutes).contains($location.path()) && !$rootScope.authenticated) {
            $rootScope.desiredPath = $location.path();
            $location.path('/login');
        }
    })
})

1 个答案:

答案 0 :(得分:2)

我建议您检查服务器端的身份验证并在客户端返回相应的消息

以下是网址帮助 http://www.espeo.pl/2012/02/26/authentication-in-angularjs-application

并在客户端编写全局处理程序以检查它

以下是示例代码:

angular.module('myApp', ['myApp.filters', 'myApp.services', 'myApp.directives'], function ($routeProvider, $locationProvider, $httpProvider) {

    var interceptor = ['$rootScope', '$q', function (scope, $q) {

        function success(response) {
            return response;
        }

        function error(response) {
            var status = response.status;

            if (status == 401) {
                window.location = "./index.html";
                return;
            }
            // otherwise
            return $q.reject(response);

        }

        return function (promise) {
            return promise.then(success, error);
        }

    }];
    $httpProvider.responseInterceptors.push(interceptor);