Question

我是android编程的初学者。我试图使用以下代码在WiFiDirect上广播消息：

public class FileTransferService扩展了IntentService {

    public static final String host= "255.255.255.255";
    InetAddress broadcastAddress = InetAddress.getByName(host);// Exception: Unknown host exception
    int port = 8888;

        protected void onHandleIntent(Intent intent) {

    Log.d(WiFiDirectActivity.TAG,"m in 1");
    Context context = getApplicationContext();

    DatagramSocket socket;
    try {
        socket = new DatagramSocket(port);

        socket.setBroadcast(true);

            socket.connect(broadcastAddress, port);
            String message = "Hello";
            byte[] buffer = message.getBytes();
            DatagramPacket packet = new DatagramPacket(
            buffer, buffer.length, broadcastAddress, port);
            socket.send(packet); // <----- Causes a SocketException
    } catch (IOException e) {
            Log.d(WiFiDirectActivity.TAG, e.getMessage(), e);
    }
          }
         }

它显示了getByName（）方法中的未知主机异常。反正有没有替换方法？我正走在正确的道路上吗？我是否需要添加任何内容来发送消息。

提前致谢

Answer 1

尝试拨打public UnknownHostException (String detailMessage)以获取detailed exception消息。

另一种调用getByName（）的方法是从here

获取

以下链接提供了设置Wi-Fi Direct广播公司的逐步说明 Connecting with Wi-Fi Direct

在Android中使用WiFi Direct进行广播

1 个答案: