我有类似于Getting data from multiple tables into single row while concatenating some values的问题,但我无法理解它,我是一个新手是SQL查询。我有几个表,我必须加入它们并连续获得一些连接数据。说明如下:
Table 1 - tasks(id,title,user_id) id title user_id tree_id -- ----- ------- ------- 1 test task 1 20 Table 2 - task_follower(id,user_id,task_id) id user_id task_id -- ------- ------- 1 1 1 Table 3 - account_user(id,name,email) id name email -- ---- ----- 1 rakesh kumar3180@gmail.com Table 2 - category(id,category) id category -- ------- 1 Project1 Table 2 - task_category(id,user_id,task_id) id task_id category_id -- ------- ------- 1 1 1
我运行的查询是:
SELECT a.*, GROUP_CONCAT(b.name SEPARATOR ',') AS member_names, GROUP_CONCAT(b.email SEPARATOR ',') AS member_emails, GROUP_CONCAT(DISTINCT d.category) SEPARATOR ',') AS categories FROM tasks AS a INNER JOIN task_followers AS c ON a.id = c.task_id INNER JOIN account_user AS b ON c.user_id = b.id INNER JOIN task_category AS i ON a.id = i.task_id INNER JOIN category AS d ON i.category_id = d.id WHERE a.id = 1 AND a.user_id = 1 AND GROUP BY a.id
作为此查询的结果,我得到:
id title user_id tree_id member_names member_emails --- ----- ------- ------- ------------- ------------- 1 test task 1 20 rakesh,rakesh kumar3180@gmail.com,kumar3180@gmail.com
我无法理解为什么名称和电子邮件重复?请帮我解决这个问题,如果你能解释我在概念上出错的地方?
我注意到当与任务关联的类别数量多于一个时,就会出现此问题。请看http://sqlfiddle.com/#!2/b96eb/1 我在那里创建了一个例子来证明我的问题。
答案 0 :(得分:1)
您可以在GROUP_CONCAT
内使用DISTINCT
,如下所示:
GROUP_CONCAT(DISTINCT b.email SEPARATOR ',') AS member_emails