Question

我第一次使用基于类的视图。我无法理解如何使用基于类的视图来实现django-endless-pagination twitter样式分页。

我能举例说明一个人会怎么做？

这是我的观点：

class EntryDetail(DetailView):
    """
    Render a "detail" view of an object.
    By default this is a model instance looked up from `self.queryset`, but the
    view will support display of *any* object by overriding `self.get_object()`.
    """
    context_object_name = 'entry'
    template_name = "blog/entry.html"
    slug_field = 'slug'
    slug_url_kwarg = 'slug'

    def get_object(self, query_set=None):
        """
        Returns the object the view is displaying.

        By default this requires `self.queryset` and a `pk` or `slug` argument
        in the URLconf, but subclasses can override this to return any object.
        """
        slug = self.kwargs.get(self.slug_url_kwarg, None)
        return get_object_or_404(Entry, slug=slug)

Answer 1

由于这是一个广泛的问题，我现在想结合几种分页解决方案。

1.使用通用ListView：

from django.views.generic import ListView

class EntryList(ListView):
    model = Entry
    template_name = 'blog/entry_list.html'
    context_object_name = 'entry_list'
    paginate_by = 10

仅使用urls.py：

会更快

url(r'^entries/$', ListView.as_view(model=Entry, paginate_by=10))

所以基本上你不需要在这个解决方案中使用django-endless-pagination。您可以在此处查看模板示例：How do I use pagination with Django class based generic ListViews?

2.使用django-endless-pagination的AjaxListView：

from endless_pagination.views import AjaxListView    
class EntryList(AjaxListView):
    model = Entry
    context_object_name = 'entry_list'
    page_template = 'entry.html'

或仅使用urls.py更快（再次）：

from endless_pagination.views import AjaxListView

url(r'^entries/$', AjaxListView.as_view(model=Entry))

参考：http://django-endless-pagination.readthedocs.org/en/latest/generic_views.html

如果有人知道不同的解决方案，请发表评论。

django-无尽的基于类的视图示例

1 个答案: