我有一个场景,我需要有大量的进度条抽屉。我无法为所有这些创建xml资源,因为我希望用户选择一种颜色,然后用它来动态创建drawable。下面是xml中的一个这样的drawable,我如何以编程方式创建这个精确的drawable?
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:id="@android:id/background">
<shape>
<solid android:color="@color/transparent" />
<stroke android:width="2px" android:color="@color/category_blue_stroke"/>
</shape>
</item>
<item android:id="@android:id/progress">
<clip>
<shape>
<solid android:color="@color/category_blue" />
<stroke android:width="2px" android:color="@color/category_blue_stroke"/>
</shape>
</clip>
</item>
</layer-list>
答案 0 :(得分:15)
通过Rajesh和g00dy提供的链接,我能够找到解决方案。
public static Drawable createDrawable(Context context) {
ShapeDrawable shape = new ShapeDrawable();
shape.getPaint().setStyle(Style.FILL);
shape.getPaint().setColor(
context.getResources().getColor(R.color.transparent));
shape.getPaint().setStyle(Style.STROKE);
shape.getPaint().setStrokeWidth(4);
shape.getPaint().setColor(
context.getResources().getColor(R.color.category_green_stroke));
ShapeDrawable shapeD = new ShapeDrawable();
shapeD.getPaint().setStyle(Style.FILL);
shapeD.getPaint().setColor(
context.getResources().getColor(R.color.category_green));
ClipDrawable clipDrawable = new ClipDrawable(shapeD, Gravity.LEFT,
ClipDrawable.HORIZONTAL);
LayerDrawable layerDrawable = new LayerDrawable(new Drawable[] {
clipDrawable, shape });
return layerDrawable;
}
此代码将创建一个drawable,它在视觉上类似于我的问题中创建的xml。