我正在使用restful web service
开发Web应用程序。
我已将hibernate
和POJO
用于mysql communication
。
我的数据库有用户表,主要是empid
。
为了获得单行,我已经将hid页面中的empid传递给了web服务,并将json对象返回到html页面(javascript用于解析)。
我用这个来获取数据库where empid=277;
//这里硬编码
new_user =(User)session.get(User.class,(long)277);
我想从其他列中检索记录,例如employeeid(NOT empid,empid是主键)
select * user where employeeid="XX-123XD"
我已经从html页面传递了employeeid
,这是一个字符串。
我写过像
这样的网络服务 @POST
@Path("/getjson")
@Produces("application/json")
public JSONObject sendjson(String employeeid) {
Gson gsonobj = new Gson();
JSONObject jsonobj = null;
SessionFactory fact;
fact = new Configuration().configure().buildSessionFactory();
User new_user = null;
Session session = fact.getCurrentSession();
Transaction tx = session.beginTransaction();
Query query = session.createQuery("from user where employeeid= :employee");
query.setParameter("employee", employeeid);
//new_user = (User) session.get(User.class, (long)277);
new_user = (User) query.list();
try {
String jsonstr = gsonobj.toJson(new_user);
jsonobj = new JSONObject(jsonstr);
} catch (JSONException ex) {
Logger.getLogger(Authneticate.class.getName()).log(Level.SEVERE, null, ex);
}
return jsonobj;
}
但是我得到了错误,
type Exception report
message com.sun.jersey.api.client.ClientHandlerException: A message body reader for Java class org.codehaus.jettison.json.JSONObject, and Java type class org.codehaus.jettison.json.JSONObject, and MIME media type text/html; charset=utf-8 was not found
description The server encountered an internal error that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: com.sun.jersey.api.client.ClientHandlerException: A message body reader for Java class org.codehaus.jettison.json.JSONObject, and Java type class org.codehaus.jettison.json.JSONObject, and MIME media type text/html; charset=utf-8 was not found
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:549)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
root cause
com.sun.jersey.api.client.ClientHandlerException: A message body reader for Java class org.codehaus.jettison.json.JSONObject, and Java type class org.codehaus.jettison.json.JSONObject, and MIME media type text/html; charset=utf-8 was not found
com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:561)
com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:517)
org.apache.jsp.HomeUser_jsp._jspService(HomeUser_jsp.java:91)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
如果我删除了Query语句,并取消注释代码,则该块为
Session session = fact.getCurrentSession();
Transaction tx = session.beginTransaction();
//Query query = session.createQuery("from user where employeeid= :employee");
//query.setParameter("employee", employeeid);
new_user = (User) session.get(User.class, (long)277);
//new_user = (User) query.list();
然后它起作用并给出作为主键的empid=277
的预期结果。
我在查询时遇到了什么问题。 还有其他方法可以让hibernate获取没有主键的数据 喜欢
`new_user = (User) session.get(User.class, employeeid);`
|
String(Not the primary key)
我获取JSON对象的jsp文件是
<%
Client client = Client.create();
WebResource service = client.resource("http://localhost:8080/ITHelpdesk/webresources/hello/getjson");
String input = request.getParameter("username");
ClientResponse cliresponse = service.type("text/html").post(ClientResponse.class,input);
JSONObject jsonobj = cliresponse.getEntity(JSONObject.class);
%>
我尝试过使用new_user = (User) query.uniqueResult();
然后也发生了同样的错误JSONObject jsonobj = cliresponse.getEntity(JSONObject.class);
谢谢
答案 0 :(得分:0)
请使用Query方法uniqueResult()。
Query query = session.createQuery("from user where employeeid= :employee");
query.setParameter("employee", employeeid);
new_user = (User) query. uniqueResult();
答案 1 :(得分:0)
您发布的客户端异常没有帮助,您能提供服务器端异常堆栈跟踪吗?我们必须知道什么是hibernate投诉
答案 2 :(得分:0)
解决,
而不是
Query query = session.createQuery("from user where employeeid= :employee");
query.setParameter("employee", employeeid);
我已添加,
Query query = session.createQuery("from user where employeeid='" + employeeid + "'");
它工作正常