Question

HI我被困在获取我需要在kendo UI GRID中显示的数据，最初我能够看到按钮，文本框和网格，但是当我在文本框中输入值然后按下我需要的按钮显示在kendo UI GRID中输入的值...

当我在谷歌浏览器中运行此应用程序时，它给出了空格，输入值后然后按下提交按钮，但是当我在IE8中运行这个时，它在启动阶段本身就给出了这样的错误.... / p>

Unhandled exception at line 238, column 37 in Function code 0x800a138f - Microsoft JScript runtime error: 'data.EmployeeDetails.EmployeeId' is null or not an object

这是我的模特

    public class TextBoxGrid
    {
        public string EnteredValue { get; set; }
        public List<EmployeeDetails> employees;
    }  
    public class ParentViewModel
    {
        public EmployeeDetails EmployeeDetails { get; set; }
        public TextBoxGrid TextBoxGrid { get; set; }
    }
    public class EmployeeDetails
    {
        public string EmployeeId { get; set; }
        public string ManagerId { get; set; }
    }

这是我的控制器

public class EnterValuesGridController : Controller
{
    private static List<EmployeeDetails> empdtls;
    public ActionResult Index( ParentViewModel model)
    {
        var viewmodel = new ParentViewModel
        {
            TextBoxGrid = new TextBoxGrid { employees = GetEmployee().ToList() }
        };
        return View(viewmodel);
    }      
    [HttpPost]
    public ActionResult PostValues(TextBoxGrid model)
    {
        TempData["enteringValue"] = model.EnteredValue;
        var viewmodel = new ParentViewModel
        {
            TextBoxGrid = new TextBoxGrid { employees = GetEmployee().ToList() }
        };
        //ParentViewModel p = new ParentViewModel();
        //TextBoxGrid t = new TextBoxGrid();
        //t.EnteredValue = "a";
        //TempData["a1"] = t.EnteredValue;
        //t.employees = GetEmployee().ToList();
        //p.TextBoxGrid = t;
        //return View("Index", p);   
        return View("Index", viewmodel);        
    }
    public  IEnumerable<EmployeeDetails> GetEmployee()
    {
        string enteredValueId =(string) TempData["enteringValue"];
        string managerId = "M" +enteredValueId;
        empdtls = new List<EmployeeDetails>();
        EmployeeDetails em1 = new EmployeeDetails();
        em1.EmployeeId = enteredValueId;
        em1.ManagerId = managerId;
        empdtls.Add(em1);
        return empdtls.AsEnumerable();
    }
    public ActionResult Orders_Read([DataSourceRequest]DataSourceRequest request)
    {
        return Json(GetOrders().ToDataSourceResult(request));
    }
    private IEnumerable<EmployeeDetails> GetOrders()
    {
        return GetEmployee().AsEnumerable();
    }
}

这是我的观点

@model KendoPratapSampleMVCApp.Models.ParentViewModel
@{
    ViewBag.Title = "Index";
}    
@using (Html.BeginForm("PostValues", "EnterValuesGrid", FormMethod.Post))
{ 
     @Html.TextBoxFor(m=>m.TextBoxGrid.EnteredValue)    
     <input type="submit" name="Submitbutton1" value="Submit1" />               
     @(Html.Kendo().Grid<KendoPratapSampleMVCApp.Models.ParentViewModel>()    
    .Name("grid")
    .Columns(columns => {
        columns.Bound(s=>s.EmployeeDetails.EmployeeId).Filterable(false).Width(100);
        columns.Bound(s => s.EmployeeDetails.ManagerId).Filterable(false).Width(100);        
    })
    .Filterable()
    .HtmlAttributes(new { style = "height:430px;" })
    .DataSource(dataSource => dataSource       
        .Ajax()
        .PageSize(20)
        .Read(read => read.Action("Orders_Read", "EnterValuesGrid"))
     )
  )        
}

我不确定我做错了什么，你能不会就这个问题提出任何想法。非常感谢....，我是否需要对UI GRID进行任何更改我尝试更改post值方法......但它对我没有用...

更新： 改变了tempData来查看Bag ...

    [HttpPost]
    public ActionResult PostValues(ParentViewModel model)
    {
        ViewBag.item = model.TextBoxGrid.EnteredValue;

        var viewmodel = new ParentViewModel
        {
            TextBoxGrid = new TextBoxGrid { employees = GetEmployee().ToList() }

        };

        //ParentViewModel p = new ParentViewModel();
        //TextBoxGrid t = new TextBoxGrid();
        //t.EnteredValue = "a";
        //TempData["a1"] = t.EnteredValue;
        //t.employees = GetEmployee().ToList();
        //p.TextBoxGrid = t;
        //return View("Index", p);   
        return View("Index", viewmodel);        
    }

    public  IEnumerable<EmployeeDetails> GetEmployee()
    {
        string enteredValueId = (string)ViewBag.item;
        string managerId = "M" +enteredValueId;
        empdtls = new List<EmployeeDetails>();
        EmployeeDetails em1 = new EmployeeDetails();
        em1.EmployeeId = enteredValueId;
        em1.ManagerId = managerId;
        empdtls.Add(em1);
        return empdtls;
    }

Answer 1

您好pratap我只是更新您的代码，

<强>模型

 public class TextBoxGrid
    {
        public string EnteredValue { get; set; }
        public List<EmployeeDetails> employees;
    }
    public class ParentViewModel
    {
        public EmployeeDetails EmployeeDetails { get; set; }
        public TextBoxGrid TextBoxGrid { get; set; }
    }
    public class EmployeeDetails
    {
        public string EnteredValue { get; set; }
        public string EmployeeId { get; set; }
        public string ManagerId { get; set; }
    }

查看

@model TwoModelInSinglePageModel.EmployeeDetails @{ ViewBag.Title = "Index"; } <script src="~/Script/Jquery-1.8.1.min.js" type="text/javascript"></script> <script src="~/Script/jquery-ui-1.8.20.min.js" type="text/javascript"></script> <script src="@Url.Content("~/Script/kendo.all.min.js")" type="text/javascript"></script> <script src="~/Script/kendo.web.min.js" type="text/javascript"></script> <script src="~/Script/kendo.aspnetmvc.min.js" type="text/javascript"></script> @using (Html.BeginForm("PostValues", "Test", FormMethod.Post)) { @Html.TextBoxFor(m => m.EnteredValue) <input type="submit" name="Submitbutton1" value="Submit1" /> @(Html.Kendo().Grid<TwoModelInSinglePageModel.EmployeeDetails>() .Name("grid") .Columns(columns => { columns.Bound(s => s.EmployeeId); columns.Bound(s => s.ManagerId); }) .Filterable() .HtmlAttributes(new { style = "height:430px;" }) .DataSource(dataSource => dataSource .Ajax() .PageSize(20) .Read(read => read.Action("Orders_Read", "Test")) ) ) }

<强>控制器

private static List<EmployeeDetails> empdtls; public ActionResult PostValues() { return View(); } [HttpPost] public ActionResult PostValues(EmployeeDetails model) { ViewBag.item = model.EnteredValue; ParentViewModel viewmodels = new ParentViewModel { TextBoxGrid = new TextBoxGrid { employees = GetEmployee().ToList() } }; ParentViewModel viewmodel = new ParentViewModel(); EmployeeDetails em1 = new EmployeeDetails(); for (int i = 0; i < viewmodels.TextBoxGrid.employees.Count(); i++) { em1.EmployeeId = viewmodels.TextBoxGrid.employees[i].EmployeeId; em1.ManagerId = viewmodels.TextBoxGrid.employees[i].ManagerId; viewmodel.EmployeeDetails = em1; } Session["EM1"] = em1; return View("PostValues", em1); } public List<EmployeeDetails> GetEmployee() { string enteredValueId = (string)ViewBag.item; string managerId = "M" + enteredValueId; empdtls = new List<EmployeeDetails>(); EmployeeDetails em1 = new EmployeeDetails(); em1.EmployeeId = enteredValueId; em1.ManagerId = managerId; if (Session["EM1"] != null) { em1 = Session["EM1"] as EmployeeDetails; empdtls.Add(em1); Session["EM1"] = null; } else { empdtls.Add(em1); } return empdtls; } public ActionResult Orders_Read([DataSourceRequest]DataSourceRequest request, EmployeeDetails model) { return Json(GetEmployee().ToDataSourceResult(request)); }

Answer 2

好的，我再次阅读你的帖子，你想在实际点击按钮时提交表格。所以，让我们尝试将值放在会话中

Session["enteringValue"] = model.EnteredValue;

您可以使用

检索它

string enteredValueId = (string)(Session["enteringValue"]);

Microsoft JScript运行时错误：'data.EmployeeDetails.EmployeeId'为null或不是对象

2 个答案: