我试图用一个linq句子解决问题,我不知道是否有可能做到这一点。 我有一个名为PRICES的表,其中包含以下字段:
pkey: int
region: int?
product_type: int
product_size: int
price: double
desc: string
唯一键是:product_type + product_size
我想做一个返回所有行WHERE region == 17的查询 (这是我的第一组行) 并且想要添加region为null的所有行 (这是我的第二组行) 但 如果两个集合中都有相同product_type和product_size的行,我想在最终结果中只是第一个集合的行。
示例:
pkey | region | product_type | product_size | price | desc
1, null, 20, 7, 2.70, salad1
2, null, 20, 3, 2.50, salad7
3, 17, 20, 7, 1.90, saladspecial
4, 17, 20, 5, 2.20, other
我想要一个返回此命令的linq查询:
2, null, 20, 3, 2.50, salad7
3, 17, 20, 7, 1.90, saladspecial
4, 17, 20, 5, 2.20, other
(请注意,丢弃带有pkey 1的行,因为pkey 3的行具有相同的product_type和product_size)
var query1 = from p in PRICES where p.region == 17
select p;
var query2 = from p in PRICES where p.region is null
select p;
问题:
如何连接query1和query2以获得预期的输出?
只需1次查询即可完成?
答案 0 :(得分:2)
以下查询仅选择区域为17
或null
的价格,请按唯一键{ p.product_type, p.product_size }
对其进行分组。然后它检查组是否包含至少一个区域为17
的价格。如果是,那么我们从组中选择该区域的所有价格(并跳过null
区域的价格)。否则我们返回整个组(它只有空区域):
var query = from p in PRICES.Where(x => x.region == 17 || x.region == null)
group p by new { p.product_type, p.product_size } into g
from pp in g.Any(x => x.region == 17) ?
g.Where(x => x.region == 17) : g
select pp;
输入:
1 null 20 7 2.7 salad1 // goes to group {20,7} with region 17 price
2 null 20 3 2.5 salad7 // goes to group {20,3} without region 17 prices
3 17 20 7 1.9 saladspecial // goes to group {20,7}
4 17 20 5 2.2 other // goes to group {20,5}
输出:
2 null 20 3 2.5 salad7
3 17 20 7 1.9 saladspecial
4 17 20 5 2.2 other
编辑上面的查询适用于内存中的对象(即LINQ to Objects),但LINQ to Entitis不是那么强大 - 它不支持嵌套查询。因此,对于Entity Framework,您需要两个查询 - 一个用于获取null
区域的价格,该区域在组中没有区域17
价格,第二个 - 来自区域17
的价格:
var pricesWithoutRegion =
db.PRICES.Where(p => p.region == 17 || p.region == null)
.GroupBy(p => new { p.product_type, p.product_size })
.Where(g => !g.Any(p => p.region == 17))
.SelectMany(g => g);
var query = db.PRICES.Where(p => p.region == 17).Concat(pricesWithoutRegion);
实际上,EF在一个UNION
查询服务器中执行两个子查询。将生成以下SQL(我删除了 desc 和 price 列以适应屏幕):
SELECT [UnionAll1].[pkey] AS [C1],
[UnionAll1].[region] AS [C2],
[UnionAll1].[product_type] AS [C3],
[UnionAll1].[product_size] AS [C4]
FROM (SELECT [Extent1].[pkey] AS [pkey],
[Extent1].[region] AS [region],
[Extent1].[product_type] AS [product_type],
[Extent1].[product_size] AS [product_size]
FROM [dbo].[Prices] AS [Extent1] WHERE 17 = [Extent1].[region]
UNION ALL
SELECT [Extent4].[pkey] AS [pkey],
[Extent4].[region] AS [region],
[Extent4].[product_type] AS [product_type],
[Extent4].[product_size] AS [product_size]
FROM (SELECT DISTINCT [Extent2].[product_type] AS [product_type],
[Extent2].[product_size] AS [product_size]
FROM [dbo].[Prices] AS [Extent2]
WHERE ([Extent2].[region] = 17 OR [Extent2].[region] IS NULL) AND
(NOT EXISTS
(SELECT 1 AS [C1] FROM [dbo].[Prices] AS [Extent3]
WHERE ([Extent3].[region] = 17 OR [Extent3].[region] IS NULL)
AND ([Extent2].[product_type] = [Extent3].[product_type])
AND ([Extent2].[product_size] = [Extent3].[product_size])
AND (17 = [Extent3].[region])
))) AS [Distinct1]
INNER JOIN [dbo].[Prices] AS [Extent4]
ON ([Extent4].[region] = 17 OR [Extent4].[region] IS NULL)
AND ([Distinct1].[product_type] = [Extent4].[product_type])
AND ([Distinct1].[product_size] = [Extent4].[product_size]))
AS [UnionAll1]
顺便说一下,我很惊讶GroupBy
被翻译成带有条件的内连接。
答案 1 :(得分:1)
我认为你应该进行1次查询,对于2次查询,我们必须重复一些事情:
//for 2 queries
var query = query1.Union(query2.Except(query2.Where(x=>query1.Any(y=>x.product_type==y.product_type&&x.product_size==y.product_size))))
.OrderBy(x=>x.pkey);
//for 1 query
//the class/type to make the group key
public class GroupKey
{
public int ProductType { get; set; }
public int ProductSize { get; set; }
public override bool Equals(object obj)
{
GroupKey gk = obj as GroupKey;
return ProductType == gk.ProductType && ProductSize == gk.ProductSize;
}
public override int GetHashCode()
{
return ProductSize ^ ProductType;
}
}
//-------
var query = list.Where(x => x.region == 17 || x.region == null)
.GroupBy(x => new GroupKey{ProductType = x.product_type, ProductSize = x.product_size })
.SelectMany<IGrouping<GroupKey,Price>,Price,Price>(x => x.Where(k => x.Count(y => y.region == 17) == 0 || k.region == 17), (x,g) => g)
.OrderBy(x=>x.pkey);