我正在尝试编写一个程序,其中客户端请求服务器拥有的核心数。我这样做如下:
客户端:
public void actionPerformed(ActionEvent e) {
try {
Socket clientSocket = new Socket("128.59.65.200", 6789);
DataOutputStream outToServer = new DataOutputStream(clientSocket.getOutputStream());
BufferedReader inFromServer = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
String numberOfCores = inFromServer.readLine();clientSocket.close();
System.out.println(numberOfCores);
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
}
});
服务器
public static void sendNumberOfCores() {
Thread coresThread = new Thread() {
public void run() {
try {
int numberOfCores;
ServerSocket welcomeSocket = new ServerSocket(6789);
while (true) {
Socket connectionSocket = welcomeSocket.accept();
DataOutputStream outToClient = new DataOutputStream(connectionSocket.getOutputStream());
numberOfCores = Runtime.getRuntime().availableProcessors();
outToClient.write(numberOfCores);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
coresThread.setName("Wait for core request thread");
coresThread.start();
}
然而,当我加载服务器并点击运行客户端代码的gui上的按钮时,没有任何反应,按钮就会卡住。造成这种情况的原因是什么?
谢谢。
答案 0 :(得分:0)
Server not initialized on the 6789 port and make sure you do that in a separate thread.
Some thing like this.
In Server class:
--Make an inner class say MyServer
class MyServer implements Runnable{
final int BACKLOG=10; //10 is the backlog,if your server wishes to serve requests.
final int PORT = 6789;
public void run(){
try {
ServerSocket serverSocket = new ServerSocket(PORT,BACKLOG); //10 is the backlog,if your server wishes to serve conncurrent requests.
while (true) {
Socket ClientConnetion = serverSocket.accept();
//Now whatever you want to do with ClientConnection socket you can call
}
} catch (Exception e) {
e.printStackTrace();
}
}
--Start this thread in you main server class
MyServer mys=new MyServer();
Thread r=new Thread(mys);
mys.start();
答案 1 :(得分:0)
当客户端上的代码等待字符串时,我发送了一个整数。