Question

在测试我的应用时，我在使用Flask-Admin创建蓝图时遇到了问题。

这是我的View类（使用SQLAlchemy）

##
# All views that only admins are allowed to see should inherit from this class.
#
class AuthView(ModelView):
    def is_accessible(self):
        return current_user.is_admin()

class UserView(AuthView):
    column_list = ('name', 'email', 'role_code')

这是我初始化视图的方式：

# flask-admin
admin.add_view(UserView(User, db.session))
admin.init_app(app)

但是，当我尝试运行多个测试时（故障总是发生在第二个测试以及随后的所有其他测试中），我总是收到以下错误消息：

======================================================================
ERROR: test_send_email (tests.test_views.TestUser)
----------------------------------------------------------------------
Traceback (most recent call last):
  File "/lib/python2.7/site-packages/nose/case.py", line 133, in run
    self.runTest(result)
  File "/lib/python2.7/site-packages/nose/case.py", line 151, in runTest
    test(result)
  File "/lib/python2.7/site-packages/flask_testing.py", line 72, in __call__
    self._pre_setup()
  File "/lib/python2.7/site-packages/flask_testing.py", line 80, in _pre_setup
    self.app = self.create_app()
  File "/tests/test_init.py", line 27, in create_app
    app = create_app(TestConfig)
  File "/fbone/app.py", line 41, in create_app
    configure_extensions(app)
  File "/fbone/app.py", line 98, in configure_extensions
    admin.add_view(UserView(User, db.session))
  File "/lib/python2.7/site-packages/flask_admin/base.py", line 484, in add_view
    self.app.register_blueprint(view.create_blueprint(self))
  File "/lib/python2.7/site-packages/flask/app.py", line 62, in wrapper_func
    return f(self, *args, **kwargs)
  File "/lib/python2.7/site-packages/flask/app.py", line 885, in register_blueprint
    (blueprint, self.blueprints[blueprint.name], blueprint.name)
AssertionError: A blueprint's name collision occurred between <flask.blueprints.Blueprint object at 0x110576910> and <flask.blueprints.Blueprint object at 0x1103bd3d0>.  Both share the same name "userview".  Blueprints that are created on the fly need unique names.

奇怪的是，这只发生在第二次测试中，而且从未在我运行应用程序时发生。

当我调试测试时，它第一次完全按照我的预期执行，并在init_app（app）之后将蓝图添加到应用程序中。第二次，当进入add_view步骤时，该过程立即停止（我认为这很奇怪，因为蓝图已在init_app（app）调用中注册？）

Answer 1

使用Flask-Admin并使用pytest进行测试时发生了同样的事情。通过将管理实例的创建移动到app工厂，我能够在不为测试创建拆卸功能的情况下修复它。

在：

# extensions.py
from flask.ext.admin import Admin
admin = Admin()

# __init__.py
from .extensions import admin

def create_app():
    app = Flask('flask_app')

    admin.add_view(sqla.ModelView(models.User, db.session))
    admin.init_app(app)

    return app

之后：

# __init__.py
from flask.ext.admin import Admin

def create_app():
    app = Flask('flask_app')

    admin = Admin()

    admin.add_view(sqla.ModelView(models.User, db.session))    
    admin.init_app(app)

    return app

因为pytest每次不再尝试在全局管理实例上注册多个视图时运行app工厂。这与典型的Flask扩展程序使用情况不一致，但它可以正常工作，并且可以防止您的应用工厂遇到Flask-Admin视图。

Answer 2

我必须将以下内容添加到我的测试用例tearDown中。它清除了在测试设置中添加到管理扩展的视图

from flask.ext.testing import TestCase
from flask.ext.admin import BaseView

# My application wide instance of the Admin manager
from myapp.extensions import admin 


class TestView(BaseView):
    ...


class MyTestCase(TestCase):
    def setUp(self):
        admin.add_view(TestView())

    def tearDown(self):
       admin._views.pop(-1)
       admin._menu.pop(-1)

这肯定是一个黑客攻击，但是当我遇到这个问题时它完成了工作。

Answer 3

以防这有助于任何人，另一种处理方法是：

class MyTestCase(TestCase):
    def setUp(self):
        admin._views = []

这样您就不必在工厂内设置Admin（）初始化。这对我来说似乎更合适。

Answer 4

以这种方式解决。仅供参考。

#YourApp/init.py
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_admin import Admin

db = SQLAlchemy()
admin = Admin(name='TuozhanOA', template_mode='bootstrap3')
def create_app(config_class=Config):
    app = Flask(name)
    app.config.from_object(Config)
    db.init_app(app)
    admin.init_app(app)
    from YourApp.main.routes import main
    app.register_blueprint(main)
    from YourApp.adminbp.routes import adminbp, user_datastore
    app.register_blueprint(adminbp)
    security = Security(app, user_datastore)
    return app

#YourApp/adminbp/routes.py
from flask import render_template, Blueprint
from YourApp.models import User, Role
from YourApp import db, admin
from flask_admin.contrib.sqla import ModelView
from wtforms.fields import PasswordField
from flask_admin.contrib.fileadmin import FileAdmin
import os.path as op

from flask_security import current_user, login_required, RoleMixin, Security, 
SQLAlchemyUserDatastore, UserMixin, utils

adminbp = Blueprint('adminbp', name)
admin.add_view(ModelView(User, db.session, category="Team"))
admin.add_view(ModelView(Role, db.session, category="Team"))

path = op.join(op.dirname(file), 'tuozhan')
admin.add_view(FileAdmin(path, '/static/tuozhan/', name='File Explore'))

测试期间创建Flask-Admin蓝图

4 个答案: