Question

我在TextBlock内找到正确的StackPanel控件时遇到了一些问题。我的标记：

<ListBox Name="lstTimeline" ItemContainerStyle="{StaticResource TwItemStyle}"
         MouseDoubleClick="lstTimeline_MouseDoubleClick">
    <ListBox.ItemTemplate>
        <DataTemplate>
            <DockPanel MaxWidth="{Binding ElementName=lstTimeline, Path=ActualWidth}">
                <Border Margin="10" DockPanel.Dock="Left"  BorderBrush="White"
                        BorderThickness="1" Height="48" Width="48" HorizontalAlignment="Center">
                    <Image Source="{Binding ThumbNail, IsAsync=True}" Height="48" Width="48" />
                </Border>
                <StackPanel Name="stkPanel" Margin="10" DockPanel.Dock="Right">
                    <TextBlock Text="{Binding UserName}" FontWeight="Bold" FontSize="18" />
                    <TextBlock Text="{Binding Text}" Margin="0,4,0,0" FontSize="14"
                               Foreground="#c6de96" TextWrapping="WrapWithOverflow" />
                    <TextBlock Text="{Binding ApproximateTime}" FontSize="14"
                               FontFamily="Georgia" FontStyle="Italic" Foreground="#BBB" />
                    <TextBlock Text="{Binding ScreenName}" Name="lblScreenName"  FontSize="14"
                               FontFamily="Georgia" FontStyle="Italic" Foreground="#BBB"
                               Loaded="lblScreenName_Loaded" />
                </StackPanel>
            </DockPanel>
        </DataTemplate>
    </ListBox.ItemTemplate>
</ListBox>

我的双击代码：

private void lstTimeline_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
    ListBoxItem lbi = (lstTimeline.SelectedItem as ListBoxItem);

    StackPanel item = lbi.FindName("stkPanel") as StackPanel;
    if (item != null)
        MessageBox.Show("StackPanel null");
    TextBlock textBox = item.FindName("lblScreenName") as TextBlock;
    if (textBox != null)
        MessageBox.Show("TextBlock null");

    MessageBox.Show(textBox.Text);
}

但StackPanel为空。如何在TextBlock中找到合适的SelectedItem？

感谢您的帮助。

Answer 1

ListBoxItem myListBoxItem = (ListBoxItem)(lstUniqueIds.ItemContainerGenerator.ContainerFromIndex(lstUniqueIds.SelectedIndex));
ContentPresenter myContentPresenter = FindVisualChild<ContentPresenter>(myListBoxItem);
DataTemplate myDataTemplate = myContentPresenter.ContentTemplate;
CheckBox target = (CheckBox)myDataTemplate.FindName("chkUniqueId", myContentPresenter);
if (target.IsChecked)
{
    target.IsChecked = false;
}
else
{
    target.IsChecked = true;
}

可以在MSDN页面FrameworkTemplate.FindName Method上找到函数FindVisualChild：

private childItem FindVisualChild<childItem>(DependencyObject obj)
    where childItem : DependencyObject
{
    for (int i = 0; i < VisualTreeHelper.GetChildrenCount(obj); i++)
    {
        DependencyObject child = VisualTreeHelper.GetChild(obj, i);
        if (child != null && child is childItem)
            return (childItem)child;
        else
        {
            childItem childOfChild = FindVisualChild<childItem>(child);
            if (childOfChild != null)
                return childOfChild;
        }
    }
    return null;
}

Answer 2

当您在寻找名称在模板中定义的内容时，可以使用特定的功能。试试这样：

private void lstTimeline_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
    ListBoxItem lbi = (lstTimeline.SelectedItem as ListBoxItem);

    StackPanel item = Template.FindName("stkPanel",lbi) as StackPanel;
    if (item != null)
        MessageBox.Show("StackPanel null");
    TextBlock textBox = Template.FindName("lblScreenName",item) as TextBlock;
    if (textBox != null)
        MessageBox.Show("TextBlock null");

    MessageBox.Show(textBox.Text);
}

Answer 3

使用get和set模型将Linq转换为xml。

var item = ...

            lstTimeline.SelectedIndex = -1;
            lstTimeline.ItemsSource = item;

在Listbox.ItemTemplate中找到控件（WPF C＃）

3 个答案: