Question

我正在尝试使用while循环创建一个骰子游戏，如果是的话。我已经成功完成了这个，但是我想弄清楚如何对游戏进行编程，这样如果没有输入数字4,6或12，它将表示无效选择并将再次询问diceChoice。有人可以帮忙吗？

到目前为止，我有......

rollAgain = "Yes" or "yes" or "y"

while rollAgain == "Yes" or "yes" or "y":
    diceChoice = input ("Which dice would you like to roll; 4 sided, 6, sided or 12 sided?")
    if diceChoice == "4":
        import random 
        print("You rolled a ", random.randint(1,4)) 
    if diceChoice == "6":
        import random
        print("You rolled a ", random.randint(1,6))
    if diceChoice == "12":
        import random
        print("You rolled a ", random.randint(1,12))

    rollAgain = input ("Roll Again?") 
print ("Thank you for playing")

Answer 1

固定While循环，整理所有重复。将导入语句移至顶部。结构化允许rollAgain和diceChoice的更多选项。

import random

rollAgain = "Yes"

while rollAgain in ["Yes" , "yes", "y"]:
    diceChoice = input ("Which dice would you like to roll; 4 sided, 6, sided or 12 sided?")
    if diceChoice in ["4","6","12"]:
        print("You rolled a ",random.randint(1,int(diceChoice)))
    else:
        print "Please input 4,6, or 12."
    rollAgain = input ("Roll Again?") 

print ("Thank you for playing")

执行此类任务：

rollAgain = "Yes" or "yes" or "y"

是不必要的 - 只输入第一个值。为此变量选择一个;你只需要一个用于它的目的。

这种作业在这里也不起作用：

while rollAgain == "Yes" or "yes" or "y":

它将再次仅检查第一个值。您要么像其他海报一样将其拆分，要么使用不同的数据结构，将它们全部合并为上面代码中的列表。

Answer 2

你应该只在顶部随机导入一次

import random  #put this as the first line

您的rollAgain声明只应将其设置为一个值

rollAgain = "yes"  # the or statements were not necessary

您忘记在后续条件中执行rollAgain ==，这是一种更简单的方式

while rollAgain.lower().startswith("y"):  #makes sure it starts with y or Y

要执行无效输入语句，您可以使用elif:和else:语句来保持简单

if diceChoice == "4":
    print("You rolled a ", random.randint(1,4)) 
elif diceChoice == "6":
    print("You rolled a ", random.randint(1,6))
elif diceChoice == "12":
    print("You rolled a ", random.randint(1,12))
else:
    print("Invalid Input, please enter either 4, 6, or 12")

你旧的while循环永远不会退出，因为你基本上是这样说的

while rollAgain == "Yes" or True or True  #because non-empty strings are treated as True

编辑，因为您询问了in语句，这是一个简短的例子

>>>5 in [1,2,3,4]
False
>>>5 in [1,2,3,4,5]
True

in语句与其他语言中的contains()类似，它检查变量是否在列表中

由于5不在列表[1,2,3,4]中，因此返回False
但是，5位于列表[1,2,3,4,5]中，因此返回True

您可以在代码中使用这几个位置，特别是如果您想确保变量位于一组选项中。我不建议你为它保持简单。

Answer 3

diceChoice = None
while diceChoice not in ["4","12","6"]:
    diceChoice = input("enter choice of dice(4,6,12)")
print "You picked %d"%diceChoice

Answer 4

我接受它：

# If you are only using one function from random
# then it seems cleaner to just import that name
from random import randint
while True:
    choice = int(input("Which dice would you like to roll; 4 sided, 6, sided or 12 sided?\n:"))
    # Using sets for 'in' comparisons is faster
    if choice in {4, 6, 12}:
        print("You rolled a", randint(1, choice))
    else:
        print("Please input 4, 6, or 12.")
    # Make the input lowercase so that it will accept anything that can be
    # interpreted as "yes".
    if input("Roll Again?\n:").lower() not in {"yes", "y"}:
        # End the game by breaking the loop
        break
# You should use an input at the end to keep the window open to see the results
input("Thank you for playing!")

骰子游戏查询while循环

4 个答案: