我有两个类,事件和用户有很多关系。
public class Event {
private int id;
private List<Users> users;
}
public class User {
private int id;
private List<Event> events;
}
我已阅读@JsonIdentityInfo注释应该有帮助,但我看不到这个例子。
答案 0 :(得分:5)
您可以通过以下方式使用@JsonIdentityInfo
和User
这两个类中的Event
:
import java.util.List;
import com.fasterxml.jackson.annotation.JsonIdentityInfo;
import com.fasterxml.jackson.annotation.ObjectIdGenerators;
@JsonIdentityInfo(generator = ObjectIdGenerators.UUIDGenerator.class, property="@UUID")
public class User
{
private int id;
private List<Event> events;
// Getters and setters
}
...和
import java.util.List;
import com.fasterxml.jackson.annotation.JsonIdentityInfo;
import com.fasterxml.jackson.annotation.ObjectIdGenerators;
@JsonIdentityInfo(generator = ObjectIdGenerators.UUIDGenerator.class, property="@UUID")
public class Event
{
private int id;
private List<User> users;
// Getters and setters
}
您可以根据需要使用任何ObjectIdGenerator
。现在,对应于多对多映射的对象的序列化和反序列化将成功:
public static void main(String[] args) throws IOException
{
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(SerializationFeature.INDENT_OUTPUT, true);
Event event1 = new Event();
event1.setId(1);
Event event2 = new Event();
event2.setId(2);
User user = new User();
user.setId(10);
event1.setUsers(Arrays.asList(user));
event2.setUsers(Arrays.asList(user));
user.setEvents(Arrays.asList(event1, event2));
String json = objectMapper.writeValueAsString(user);
System.out.println(json);
User deserializedUser = objectMapper.readValue(json, User.class);
System.out.println(deserializedUser);
}
希望这有帮助。
答案 1 :(得分:1)
我来到这里&#34;谷歌搜索&#34;,所以我最终使用@ Jackall的anwers,带一点mod
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "id")
这是因为我的DTO有一个名为&#34; id&#34;的属性,就像问题中的事件和用户类一样。
答案 2 :(得分:0)
尝试在JsonIdentityInfo注释中使用“scope”属性:
@JsonIdentityInfo(
generator = ObjectIdGenerators.UUIDGenerator.class,
property="@UUID",
scope=YourPojo.class
)