Question

我有XML文件，如下所示

<?xml version="1.0" standalone="yes"?>
<ShippersDataSet xmlns="http://www.tempuri.org/ShippersDataSet.xsd">
   <Shippers>
      <ShipperID>1</ShipperID>
      <CompanyName>Speedy Express</CompanyName>
      <Phone>(503) 555-9831</Phone>
   </Shippers>
   <Shippers>
      <ShipperID>2</ShipperID>
      <CompanyName>United Package</CompanyName>
      <Phone>(503) 555-3199</Phone>
   </Shippers>
   <Shippers>
      <ShipperID>3</ShipperID>
      <CompanyName>Federal Shipping</CompanyName>
      <Phone>(503) 555-9931</Phone>
   </Shippers>
</ShippersDataSet>

我有以下XML数据输入：

string XMLpath, string query

查询：

<Query>
   <ElementPath> Shippers</ElementPath>
</Query>

我需要添加

如下所示，（我已经在SQL中实现了）我需要为XML数据添加相同的方式

var list = new List<Myclassdef>();
using (var con = new SqlConnection(Settings.Default.ConnectionString))
{
    using (var cmd = new SqlCommand("SELECT ... WHERE Col1=@param1", con))
    {
        cmd.Parameters.AddWithValue("@param1", "value1");
        // ...
        con.Open();
        using (var reader = cmd.ExecuteReader())
        {
            while (reader.Read())
            {
                Myclassdef data = new Myclassdef();
                data.Data = new Dictionary<string, object>();
                for (int i = 0; i < reader.FieldCount; i++)
                {
                    data.Data.Add(reader.GetName(i), reader[i]);
                }
                list.Add(data);
            }
        }
    }
}

我有以下XML数据输入：

string XMLpath, string query

查询：

<Query><ElementPath> Shippers</ElementPath></Query>

Answer 1

试试这个：

class Program
{
    static void Main(string[] args)
    {
        var list = new List<Myclassdef>();
        var query = XDocument
            .Parse("<Query><ElementPath> Shippers</ElementPath></Query>");
        var doc = XDocument.Parse(File.ReadAllText("xml.xml"));

        doc.Descendants(
            XName.Get(
                    query.Root.Value.Trim(),
                    doc.Root.GetDefaultNamespace().NamespaceName))
            .ToList()
            .ForEach(e =>
            {
                var data = new Myclassdef();
                data.Data = e
                    .Elements()
                    .Select(c => new
                    {
                        Name = c.Name.LocalName,
                        Value = (object)c.Value
                    })
                    .ToDictionary(c => c.Name, c => c.Value);
                list.Add(data);
            });
    }
}

Answer 2

您可以使用Linq to XML（命名空间System.Xml.Linq）：

XDocument document = XDocument.Load(stream); // load the xml into an XDocument from a stream

// select the first of a specific element
IEnumerable<XElement> elements = from shippers in document.Descendants("Shippers") select shippers;
XElement element = (XElement)elements.First().FirstNode;

// loop through all the elements inside that element
foreach (XNode node in elements.First().Nodes())
{
   // do something with elements
}

如何使用XML中的列名获取数据？

2 个答案: