Question

在这种情况下，我想在一列中找到包含名称steve的所有记录，在另一列中找到包含名称steve的所有记录。我知道我错过了一个操作员，但我不知道哪个

            SELECT firstname,lastname,middlename,company_name, 
                    primary_emailaddress,alternate_emailaddress,personal_address_line1,
                    personal_address_line2,personal_address_city,facebook_username,
                    twitter_username,googleplus_username,linkedin_username,
                    personal_website_url,birthday_month,notes,personal_address_zipcode,
                    company_address_zipcode,home_phonenumber,company_phonenumber,
                    cell_phonenumber,birthday_day,birthday_year,hash,image_file
             FROM contacts
             WHERE (
                MATCH(
                    firstname,lastname,
                    primary_emailaddress,alternate_emailaddress,personal_address_line1,
                    personal_address_city,company_name,
                    company_address_line1,company_address_city,
                    facebook_username,twitter_username,googleplus_username,linkedin_username,
                    personal_website_url
                )
                AGAINST ('Steve email@email.com' IN BOOLEAN MODE))

Answer 1

除非你真的看过每一个领域，（即约翰史蒂文森被认为是'史蒂夫'的比赛），你可以做得更简单......

select *
from contacts

where firstname like '%Steve%'
 and (primary_emailaddress like '%email@email.com%' or alternate_emailaddress like '%email@email.com%')

Answer 2

Match比like比较快。我认为你可以在where条款中执行两次：

        SELECT firstname,lastname,middlename,company_name, 
                primary_emailaddress,alternate_emailaddress,personal_address_line1,
                personal_address_line2,personal_address_city,facebook_username,
                twitter_username,googleplus_username,linkedin_username,
                personal_website_url,birthday_month,notes,personal_address_zipcode,
                company_address_zipcode,home_phonenumber,company_phonenumber,
                cell_phonenumber,birthday_day,birthday_year,hash,image_file
         FROM contacts
         WHERE MATCH (firstname) AGAINST ('Steve' IN BOOLEAN MODE) > 0 and
               MATCH (primary_emailaddress, alternate_emailaddress)
                     AGAINST ('email@email.com' IN BOOLEAN MODE) > 0;

匹配语句间隔词返回多列的结果

2 个答案: