Question

这是一个艰难的，至少对我而言。基本上我想做的是通过Javascript获取此JSON数据的每一行的每一个值：

{"id":2,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":3,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":4,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":5,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":6,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":7,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":8,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":9,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":10,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":31,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":32,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":33,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":34,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":35,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":36,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":37,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":38,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":39,"url":"image.png","x":19,"y":10,"user_id":20}
{"id":40,"url":"image.png","x":19,"y":10,"user_id":20}

我以这种方式生成它（在我的PHP文件中）：

$db->where('user_id', '20');
$results = $db->get('profile_stickers');

foreach ($results as $parameters => $values) { 
       echo json_encode($values);
}

我尝试过很多与jQuery $.each相关的代码，但没有运气，代码永远不会有效。我希望得到每一个价值，因为我将在一个页面上显示它们，具有正确的位置和图像。有谁知道获取每一行的正确功能？像PHP的$row['foo']。

-----编辑------

我是这样做的：

$.get('/Application/Ajax/__ajaxProfile.php?a=GetWidgets', function(data) {

var json = data;

for (i=0;i<json.length;i++){
    var obj = json[i];
    for (var key in obj) {
        document.getElementById("log").innerHTML += key+": "+obj[key]+"<br />";
    }
    document.getElementById("log").innerHTML += "<br />";
} 

});

但问题是，它会返回这样的数据：

0：“ 0：[ 0：{ 0：我 0：d 等。

----编辑-----

现在修复了，它是“$ .get”的东西。

Answer 1

这可能是你想要的。

$db->where('user_id', '20');
$results = $db->get('profile_stickers');

$arr = array();

foreach ($results as $parameters => $values) {

    $arr[] = $values;

}

echo json_encode($arr);

Answer 2

这可能不是您正在寻找的，但这是一种在javascript中通过所有内容的方式。

您基本上需要将其存储为JSON对象数组：

var json = [
{"id":2,"url":"image.png","x":19,"y":10,"user_id":20},
{"id":3,"url":"image.png","x":19,"y":10,"user_id":20},
...etc
]

然后你可以像这样遍历数组和对象：

for (i=0;i<json.length;i++){
  var obj = json[i];
  for (var key in obj) {
    document.write(key+": "+obj[key]);
  }
}

http://jsfiddle.net/Y4uAx/

获取PHP中生成的每一行JSON数据

2 个答案: