我正在尝试滑动信息,但它不起作用。这是我的代码:
<div Class="article">
<div id="ebook1">Ebook1</div>
<div id="infoOfEbook1">
Download The Ebook1 From Here.
</div>
</div>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.0.3.js">
$(document).ready(function(){
$("#ebook1").click(function(){
$("#infoOfEbook1").slideToggle("slow");
});
});
</script>
答案 0 :(得分:7)
您不会将代码放在带有src的脚本标记内。将其更改为:
<script type="text/javascript" src="http://code.jquery.com/jquery-2.0.3.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#ebook1").click(function(){
$("#infoOfEbook1").slideToggle("slow");
});
});
</script>