Question

这是我的表格：

<div id="HomeAgenda">
<div id="HomeAgendaTitle">Agenda</div>
    <div id="HomeAgendaCreate">
        <form method="post" action="#">
            <input type="text" name="HomeAgendaCreateTitle" id="HomeAgendaCreateTitle" placeholder="Subject" /><br>
            <input type="text" name="HomeAgendaCreateLocation" id="HomeAgendaCreateLocation" placeholder="Location" /><br>
            <input type="text" name="HomeAgendaCreateDate" id="HomeAgendaCreateDate" placeholder="Date" />
            <input type="text" name="HomeAgendaCreateTime" id="HomeAgendaCreateTime" placeholder="Time" /><br>
            <input type="text" name="HomeAgendaCreateNotes" id="HomeAgendaCreateNotes" placeholder="Notes" />
            <input type="submit" name="HomeAgendaCreateSubmit" id="HomeAgendaCreateSubmit" value="Save" />
        </form>
    </div>
</div>

这是我的php：

<?php
$SetAgendaAppointment = @$_POST['HomeAgendaCreateSubmit'];
$SetAgendaTitle = @$_POST['HomeAgendaCreateTitle'];
$SetAgendaLocation = @$_POST['HomeAgendaCreateLocation'];
$SetAgendaDate = @$_POST['HomeAgendaCreateDate'];
$SetAgendaTime = @$_POST['HomeAgendaCreateTime'];
$SetAgendaNotes = @$_POST['HomeAgendaCreateNotes'];
if($SetAgendaAppointment) {
    mysql_query("INSERT INTO agenda VALUES('$SetAgendaTitle','$SetAgendaLocation','$SetAgendaDate','$SetAgendaTime','$SetAgendaNotes','$user_id')");
}
?>

这是我的数据库连接代码：

<?php
mysql_connect("localhost","root","250317") or die(mysql_error());
mysql_select_db("bakpakk");
?>

在我从表单提交信息后的页面上，没有任何反应。当我检查议程表时，没有提交任何内容，phpmyadmin在表中返回零行。我似乎无法弄清楚为什么？提交数据后，如果表格中已有任何数据，则表格中不会输入更多数据。我们非常感谢您提供帮助。

Answer 1

添加一些错误捕获代码，以便查看查询是否出错。

if($SetAgendaAppointment) {
    $SQL = "INSERT INTO agenda  VALUES('$SetAgendaTitle','$SetAgendaLocation','$SetAgendaDate','$SetAgendaTime','$SetAgendaNotes','$user_id')";
    //ensure your creating the proper statement
    var_dump($SQL);
    $result = mysql_query($SQL); 

    if (!$result) {
        die('Invalid query: ' . mysql_error());
    }

}

Answer 2

//ensure you're getting your variables
vardump($_POST);
if($SetAgendaAppointment) {
    $SQL = "INSERT INTO agenda VALUES('$SetAgendaTitle','$SetAgendaLocation','$SetAgendaDate','$SetAgendaTime','$SetAgendaNotes','$user_id')";
    //ensure you're creating the proper statement
    var_dump($SQL);
    mysql_query($SQL); // what are you doing with this? you're just running it and not saving it to a var?
}

我的查询不起作用。没有信息发送到表格

2 个答案: