查找和比较数组值

Question

假设我们有两个数组

 array1 = [1,2,3,6,3,5,2,5,2,4,3]
 array2 = [3,4,5]

如何找到位于array2内的值“3”，然后比较array1中的相同内容。感谢任何帮助。

感谢。

Answer 1

类似的问题：How to remove specifc value from array using jQuery

从链接页面（用你的值替换它们）：

var array1 =[1,2,3,6,3,5,2,5,2,4,3];
var array2 =[1,2,3] 
var removeItem = array2[jQuery.inArray(3,array2)]; 

//jQuery.inArray returns the index where the value (3) first appears in the array (array2)

array1 = jQuery.grep(array1, function(value) {
    return value != removeItem;
});
console.log(array1); //[1,2,6,5,2,5,2,4]

Answer 2

试试这个：

function checkValueInArray(x){
    if(array1.indexOf(x) != -1 && array2.indexOf(x) != -1){
        //both arrays have this value and there indexes are
        //array1.indexOf(x);
        //array2.indexOf(x);
    }
}

---

checkValueInArray("3");

Answer 3

尝试

var arrayA = [1,2,3,6,3,5,2,5,2,4,3];
var arrayB = [3,4,5];
var arrayC = []; 

$('.arrayA').text('ArrayA: ' + arrayA);
$('.arrayB').text('ArrayB: ' + arrayB);

$.each(arrayA, function(indexA,valueA) {
    $.each(arrayB, function(indexB, valueB){
        if(valueA == valueB)
        {
            alert(valueA);
            alert(valueB);            
            return false;             
        }
    });
});

Answer 4

尝试索引

if(array1.indexOf("3") != -1){
   //exists
}