Question

我有来自服务器的以下日志文件，我想从以下字符串中提取xml。

2:00:11 PM >>Response: <?xml version="1.0" encoding="UTF-8"?>

<HotelML xmlns="http://www.xpegs.com/v2001Q3/HotelML"><Head><Route Destination="TR" Source="00"><Operation Action="Create" App="UltraDirect-d1c1_" AppVer="V1_1" DataPath="/HotelML" StartTime="2013-07-31T08:33:13.223+00:00" Success="true" TotalProcessTime="711"/></Route>............

</HotelML>


3:00:11 PM >>Response: <?xml version="1.0" encoding="UTF-8"?>

<HotelML xmlns="http://www.xpegs.com/v2001Q3/HotelML"><Head><Route Destination="TR" Source="00"><Operation Action="Create" App="UltraDirect-d1c1_" AppVer="V1_1" DataPath="/HotelML" StartTime="2013-07-31T08:33:13.223+00:00" Success="true" TotalProcessTime="711"/></Route>............

</HotelML>

5:00:11 PM >>Response: <?xml version="1.0" encoding="UTF-8"?>

<HotelML xmlns="http://www.xpegs.com/v2001Q3/HotelML"><Head><Route Destination="TR" Source="00"><Operation Action="Create" App="UltraDirect-d1c1_" AppVer="V1_1" DataPath="/HotelML" StartTime="2013-07-31T08:33:13.223+00:00" Success="true" TotalProcessTime="711"/></Route>............

</HotelML>

我已经编写了以下正则表达式，但它只匹配字符串中的第一个条目。但我想将所有xml字符串作为集合返回。

(?<= Response:).*>.*</.*?>

Answer 1

为什么不匹配<HotelML到</HotelML？

类似的东西：

<HotelML .*</HotelML>

或者，只需逐行浏览文件，并在找到与

匹配的行时

^.* PM >>Response:.*$

将以下行读作xml，直到下一个匹配的行...

Answer 2

这是另一种方法，应该为您留下List<XDocument>：

using System.IO;
using System.Linq;
using System.Text.RegularExpressions;
using System.Xml.Linq;

class Program
{
    static void Main(string[] args)
    {

        var input = File.ReadAllText("text.txt");
        var xmlDocuments = Regex
            .Matches(input, @"([0-9AMP: ]*>>Response: )")
            .Cast<Match>()
            .Select(match =>
                {
                    var currentPosition = match.Index + match.Length;
                    var nextMatch = match.NextMatch();
                    if (nextMatch.Success == true)
                    {
                        return input.Substring(currentPosition,
                            nextMatch.Index - currentPosition);
                    }
                    else
                    {
                        return input.Substring(currentPosition);
                    }
                })
            .Select(s => XDocument.Parse(s))
            .ToList();
    }
}

使用正则表达式从字符串中提取xml

2 个答案: