我正在尝试使用WhatsApp的自定义URL方案发送一些带有URL的文本。为此目的,显然只有一个有效参数:text
:
NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?text=Hello%2C%20World!"];
当我想将自己的URL附加到该文本时,问题就出现了。我选择使用它编码:
NSString *encodedURLString = (NSString *)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(
NULL,
(CFStringRef)urlAbsoluteString,
NULL,
(CFStringRef)@"!*'();:@&=+$,/?%#[]",
kCFStringEncodingUTF8 ));
网址与文本一起发送到WhatsApp,但不会在WhatsApp的一侧解码:
有什么想法吗?谢谢!
答案 0 :(得分:10)
您正确接近它,但似乎网址是双重编码的。确保消息和URL仅编码一次。
使用相同的编码方法,您可以这样做:
NSString *urlAbsoluteString = @"Hello World! http://yayvisitmysiteplease.com?funky=parameter&stuff";
NSString *encodedURLString = ...
这应该为您提供执行的URL:
whatsapp://send?text=Hello%20World%21%20http%3A%2F%2Fyayvisitmysiteplease.com%3Ffunky%3Dparameter%26stuff
就像你期望的那样进入WhatsApp。 (我证实了双重确定。)
答案 1 :(得分:10)
这是在WhatsApp
中发送文本和网址的完整代码 NSString * msg = @"Application%20Name%20https://itunes.apple.com/YOUR-URL";
msg = [msg stringByReplacingOccurrencesOfString:@":" withString:@"%3A"];
msg = [msg stringByReplacingOccurrencesOfString:@"/" withString:@"%2F"];
msg = [msg stringByReplacingOccurrencesOfString:@"?" withString:@"%3F"];
msg = [msg stringByReplacingOccurrencesOfString:@"," withString:@"%2C"];
msg = [msg stringByReplacingOccurrencesOfString:@"=" withString:@"%3D"];
msg = [msg stringByReplacingOccurrencesOfString:@"&" withString:@"%26"];
NSString * urlWhats = [NSString stringWithFormat:@"whatsapp://send?text=%@",msg];
NSURL * whatsappURL = [NSURL URLWithString:urlWhats];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL])
{
[[UIApplication sharedApplication] openURL: whatsappURL];
}
else
{
UIAlertView * alert = [[UIAlertView alloc] initWithTitle:@"WhatsApp not installed." message:@"Your device has no WhatsApp installed." delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
答案 2 :(得分:2)
它适用于Whats app上的Share Link
NSString * url = [NSString stringWithFormat:@"http://video...bla..bla.."];
url = (NSString*)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(NULL,(CFStringRef) url, NULL,CFSTR("!*'();:@&=+$,/?%#[]"),kCFStringEncodingUTF8));
NSString * urlWhats = [NSString stringWithFormat:@"whatsapp://send?text=%@",url];
NSURL * whatsappURL = [NSURL URLWithString:urlWhats];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
[[UIApplication sharedApplication] openURL: whatsappURL];
} else {
// can not share with whats app
}