Question

我有一个像这样的HTML文件：

<div id="note">
 <a name="overview"></a>
 <h3>Overview</h3>
 <p>some text1...</p>
 <a name="description"></a>
 <h3>Description</h3>
 <p>some text2 ...</p>
</div>
                              `

我想为每个标题检索段落。例如，概述：一些text1 描述：一些文字2 ... 我想用xpath在python中写这个。谢谢。

Answer 1

找到所有h3标记，迭代它们，然后在迭代循环的每一步中，找到下一个兄弟标记p：

import urllib2
from lxml import etree

URL = "http://www.kb.cert.org/vuls/id/628463"
response = urllib2.urlopen(URL)

parser = etree.HTMLParser()
tree = etree.parse(response, parser)

for header in tree.iter('h3'):
    paragraph = header.xpath('(.//following-sibling::p)[1]')
    if paragraph:
        print "%s: %s" % (header.text, paragraph[0].text)

打印：

Overview: The Ruby on Rails 3.0 and 2.3 JSON parser contain a vulnerability that may result in arbitrary code execution.
Description: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
Impact: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
Solution: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
Vendor Information : Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
CVSS Metrics : Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
References: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
Credit: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability.
Feedback: If you have feedback, comments, or additional information about this vulnerability, please send us 
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如何使用xpath选择以下兄弟标记

1 个答案: