Question

我的代码是否有理由不想写入我的文本文件：guestbook.txt？

<?php
//Create a variable called $file that holds the guestbook.txt
$file= "guestbook.txt";
//Create other variables
$name= $_REQUEST['name'];
$message= $_REQUEST['message'];
//Check to make sure that all fields are populated 
if(empty($name) || empty($message)) 
{
    echo "<center><h3>Sorry, all fields are required</h3><center>";
}
else 
{
 /*Where $fp is the file pointer, and fopen Opens file or URL, $file is the $file(message.txt) and "a" means 
 Open for writing only; place the file pointer at the end of the file. If the file does not exist, attempt to create it.*/
$fp = fopen($file,"a");
 //Use frwrite to write the write contents of string  to the file stream pointed to by handle $fp.
fwrite($fp, '<font size="3">
<br />
<br />
Name: '.$name.'<br />
<br />
<br />Message: '.$message.'<br />
');

 // Close the file pointed to by $fp.
fclose($fp);

echo '<font size="3">
<p align="center">Thank you '.$name.' for signing the Guestbook</p>
</font>'; 
}
?>

Answer 1

尝试使用

打开错误报告

error_reporting(E_ALL);

如果您没有写入权限，可以看到任何错误：

警告：fopen（guestbook.txt）：无法打开流：权限被拒绝.....

Answer 2

对我来说，对于http / apache / nobody用户来说，无法正确设置目录的权限。

Answer 3

尝试为guestbook.txt文件指定路径，以便知道它的位置，并确保权限正确。

Answer 4

如果您已禁用错误报告，

error_reporting（E_ALL）可能无法帮助您，您可以尝试以下方式启用错误报告第一次：

ini_set（'error_reporting'，'on'）; 的error_reporting（E_ALL）;

Answer 5

应该是因为，用户（apache用户）没有写入权限（或）用户没有权限在该文件夹中创建文件，如果该文件尚不存在。启用错误报告将有助于调试..

php代码不会写入文本文件

5 个答案: