我是angularjs的新手,想要点击复选框创建模型数组,下面是我的代码..
$scope.selectedAlbumSongs = [{
'name': 'song1',
'url': 'http://test/song1.mp3'
}, {
'name': 'song2',
'url': 'http://test/song2.mp3'
}, {
'name': 'song3',
'url': 'http://test/song3.mp3'
}];
$scope.playList = {};
HTML:
<fieldset data-role="controlgroup">
<legend>Select songs to play</legend>
<label ng-repeat="song in selectedAlbumSongs">
<input type="checkbox" name="{{song.url}}" id="{{song.name}}" ng-model="playList[song.url]">
<label for="{{song.name}}">{{song.name}}</label>
</label>
</fieldset>
当我点击复选框
时,上面的代码更新了playList,如下所示{
"http://test/test1.mp3": true,
"http://test/test2.mp32": true,
"http://test/test3.mp3": false
}
但我想以下面的格式创建ng-model,并在取消选中该复选框时删除该对象(例如,如果取消选中song3,则从该数组中删除song3对象)。你能告诉我怎么写这个逻辑吗?
预期:
[{
name: "song1",
url: "http://test/song1.mp3"
}, {
name: "song2",
url: "http://test/song2.mp3"
}]
答案 0 :(得分:45)
你可以这样做:
$scope.selectedAlbumSongs = [ { 'name': 'song1', 'url': 'http://test/song1.mp3' }, { 'name': 'song2', 'url': 'http://test/song2.mp3' }, {'name': 'song3', 'url': 'http://test/song3.mp3' }];
$scope.selectedSongs = function () {
$scope.playList = $filter('filter')($scope.selectedAlbumSongs, {checked: true});
}
然后,在选择更改时简单调用selectedSongs():
<input type="checkbox" name="{{song.url}}" id="{{song.name}}" ng-model="song.checked" ng-change="selectedSongs()">
请参阅演示here