我有一个需要更新的查询,以允许用户过滤掉待处理的应用程序。我已经创建了参数并试图实现使用案例,但它无法正常工作或提供有关如何纠正它的任何错误消息。代码是:
select distinct pers.person_fname,
pers.person_mname,
pers.person_lname,
le.nationalprovidernumber NPN,
lic.licensenumber LICENSE_NUMBER,
adr.address_line1 ADDRESS1,
adr.address_line2 ADDRESS2,
adr.address_line3 ADDRESS3,
adr.city CITY,
sp.state_province_name STATE,
adr.postal_code ZIP_CODE,
eml.email,
rtp.residencetype_name RESIDENCY,
ltp.licensetype_name LICENSE_TYPE,
lic.expirationdate DATE_OF_EXPIRATION
from odilic_admin.license lic
inner join odilic_admin.licenseststimeline lst
on lic.license_id = lst.license_id
inner join odilic_admin.licenseststype lstp
on lst.licenseststype_id = lstp.licenseststype_id
inner join odilic_admin.licensedef ldef
on lic.licensedef_id = ldef.licensedef_id
inner join odilic_admin.licensetype ltp
on ldef.licensetype_id = ltp.licensetype_id
inner join odilic_admin.residencetype rtp
on ldef.residencetype_id = rtp.residencetype_id
inner join odilic_admin.licensingentity le
on lic.licensingentity_id = le.licensingentity_id
inner join odilic_admin.individual ind
on le.licensingentity_id = ind.licensingentity_id
inner join odidir_admin.person pers
on ind.person_id = pers.person_id
left outer join odidir_admin.person_address_rel par
on pers.person_id = par.person_id
left outer join odidir_admin.address adr
on par.address_id = adr.address_id
left outer join odidir_admin.address_type atp
on adr.address_type_id = atp.address_type_id
left outer join odidir_admin.state_province sp
on adr.state_province_id = sp.state_province_id
left outer join
(select pr.person_id, em.email_id, em.email
from odidir_admin.person pr,
odidir_admin.person_email_rel pe,
odidir_admin.email em
where pr.person_id = pe.person_id
and pe.email_id = em.email_id
and email_type_id = 2) eml
on pers.person_id = eml.person_id
where
ltp.licensetype_id in (:License_type)
and lstp.licenseststype_name = 'Active'
and atp.address_type_name = 'Mailing Licensing'
and (lic.expirationdate >= current_date and
trunc(lic.expirationdate) = :Expiration_Date)
and sysdate between lst.periodbegindate and lst.periodenddate
order by lic.licensenumber
为了获取待处理的应用程序,我需要访问表odilic_admin.licenseappl并过滤掉appststype = 2(pending)的所有许可证。为此,我在最后一个左外连接之前为查询添加了一个连接,并在底部选择了这个参数时添加了一个case。
select distinct pers.person_fname,
pers.person_mname,
pers.person_lname,
le.nationalprovidernumber NPN,
lic.licensenumber LICENSE_NUMBER,
adr.address_line1 ADDRESS1,
adr.address_line2 ADDRESS2,
adr.address_line3 ADDRESS3,
adr.city CITY,
sp.state_province_name STATE,
adr.postal_code ZIP_CODE,
eml.email,
rtp.residencetype_name RESIDENCY,
ltp.licensetype_name LICENSE_TYPE,
lic.expirationdate DATE_OF_EXPIRATION
from odilic_admin.license lic
inner join odilic_admin.licenseststimeline lst
on lic.license_id = lst.license_id
inner join odilic_admin.licenseststype lstp
on lst.licenseststype_id = lstp.licenseststype_id
inner join odilic_admin.licensedef ldef
on lic.licensedef_id = ldef.licensedef_id
inner join odilic_admin.licensetype ltp
on ldef.licensetype_id = ltp.licensetype_id
inner join odilic_admin.residencetype rtp
on ldef.residencetype_id = rtp.residencetype_id
inner join odilic_admin.licensingentity le
on lic.licensingentity_id = le.licensingentity_id
inner join odilic_admin.individual ind
on le.licensingentity_id = ind.licensingentity_id
inner join odidir_admin.person pers
on ind.person_id = pers.person_id
left outer join odidir_admin.person_address_rel par
on pers.person_id = par.person_id
left outer join odidir_admin.address adr
on par.address_id = adr.address_id
left outer join odidir_admin.address_type atp
on adr.address_type_id = atp.address_type_id
left outer join odidir_admin.state_province sp
on adr.state_province_id = sp.state_province_id
**left outer join odilic_admin.licenseappl appl
on lic.licensingentity_id = appl.licenseappl_id**
left outer join
(select pr.person_id, em.email_id, em.email
from odidir_admin.person pr,
odidir_admin.person_email_rel pe,
odidir_admin.email em
where pr.person_id = pe.person_id
and pe.email_id = em.email_id
and email_type_id = 2) eml
on pers.person_id = eml.person_id
where
ltp.licensetype_id in (:License_type)
and lstp.licenseststype_name = 'Active'
and atp.address_type_name = 'Mailing Licensing'
and (lic.expirationdate >= current_date and
trunc(lic.expirationdate) = :Expiration_Date)
and sysdate between lst.periodbegindate and lst.periodenddate
**case :pending when = yes then appl.applststype_id !=2
end**
order by lic.licensenumber
除了这种情况,我还尝试使用具有相同结果的IF。这看起来像:
if :Pending = 1
then
and appl.applststype_id != 2;
end if;
非常感谢任何帮助让我超越这一点,我一定会投票并选择最正确的答案来帮助我解决这个问题。
答案 0 :(得分:1)
假设您的:pending
参数是一个数字,其中值为1表示要排除待处理的许可证,并且您只想排除待处理的许可证应用程序,请尝试添加以下条件代替您现有的case
条款:
and (:pending <> 1 or appl.applststype_id !=2)