大家好我想问一下。如何使用条件更新数据库中的多个行。 因为我有更新我的表的问题。 这就是我需要做的。我有2个表,一个是ref_cities,一个是ref_draft
在我的ref_cities中,我有一个专栏
mysql> desc ref_cities
+---------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+---------------+--------------+------+-----+---------+-------+
| id | int(11) | NO | PRI | NULL | |
| name | varchar(255) | YES | | NULL | |
| province_id | int(11) | YES | | NULL | |
| province_code | varchar(5) | YES | | NULL | |
+---------------+--------------+------+-----+---------+-------+
4 rows in set (0.01 sec)
在我的ref_draft中,我有这个
mysql> desc ref_draft;
+--------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+-------------+------+-----+---------+----------------+
| id | int(10) | NO | PRI | NULL | auto_increment |
| municipality | varchar(50) | YES | | NULL | |
| name | varchar(50) | YES | | NULL | |
| city_code | int(11) | YES | | NULL | |
+--------------+-------------+------+-----+---------+----------------+
4 rows in set (0.03 sec)
在我的ref_cities值中(我出于示例目的仅列出了一行)
mysql> select * from ref_cities where name like '%manila%';
+------+--------+-------------+---------------+
| id | name | province_id | province_code |
+------+--------+-------------+---------------+
| 1976 | Manila | 58 | MNL |
+------+--------+-------------+---------------+
1 row in set (0.00 sec)
在我的ref_draft值中
mysql> select * from ref_draft where municipality like '%manila%';
+-----+----------------+----------------+-----------+
| id | municipality | name | city_code |
+-----+----------------+----------------+-----------+
| 1 | CITY OF MANILA | Barangay 1 | NULL |
| 2 | CITY OF MANILA | Barangay 2 | NULL |
| 3 | CITY OF MANILA | Barangay 3 | NULL |
| 4 | CITY OF MANILA | Barangay 4 | NULL |
| 5 | CITY OF MANILA | Barangay 5 | NULL |
| 6 | CITY OF MANILA | Barangay 6 | NULL |
| 7 | CITY OF MANILA | Barangay 7 | NULL |
| 8 | CITY OF MANILA | Barangay 8 | NULL |
| 9 | CITY OF MANILA | Barangay 9 | NULL |
| 10 | CITY OF MANILA | Barangay 10 | NULL |
| 11 | CITY OF MANILA | Barangay 11 | NULL |
| 12 | CITY OF MANILA | Barangay 12 | NULL |
| 13 | CITY OF MANILA | Barangay 13 | NULL |
| 14 | CITY OF MANILA | Barangay 14 | NULL |
| 15 | CITY OF MANILA | Barangay 15 | NULL |
| 16 | CITY OF MANILA | Barangay 16 | NULL |
这应该是样本输出
+-----+----------------+----------------+-----------+
| id | municipality | name | city_code |
+-----+----------------+----------------+-----------+
| 1 | CITY OF MANILA | Barangay 1 | 1976 |
| 2 | CITY OF MANILA | Barangay 2 | 1976 |
| 3 | CITY OF MANILA | Barangay 3 | 1976 |
| 4 | CITY OF MANILA | Barangay 4 | 1976 |
| 5 | CITY OF MANILA | Barangay 5 | 1976 |
| 6 | CITY OF MANILA | Barangay 6 | 1976 |
| 7 | CITY OF MANILA | Barangay 7 | 1976 |
| 8 | CITY OF MANILA | Barangay 8 | 1976 |
| 9 | CITY OF MANILA | Barangay 9 | 1976 |
| 10 | CITY OF MANILA | Barangay 10 | 1976 |
| 11 | CITY OF MANILA | Barangay 11 | 1976 |
| 12 | CITY OF MANILA | Barangay 12 | 1976 |
| 13 | CITY OF MANILA | Barangay 13 | 1976 |
| 14 | CITY OF MANILA | Barangay 14 | 1976 |
| 15 | CITY OF MANILA | Barangay 15 | 1976 |
| 16 | CITY OF MANILA | Barangay 16 | 1976 |
但我知道
+----+----------------+-------------+-----------+
| id | municipality | name | city_code |
+----+----------------+-------------+-----------+
| 1 | CITY OF MANILA | Barangay 1 | 1301 |
| 2 | CITY OF MANILA | Barangay 2 | 1301 |
| 3 | CITY OF MANILA | Barangay 3 | 1301 |
| 4 | CITY OF MANILA | Barangay 4 | 1301 |
| 5 | CITY OF MANILA | Barangay 5 | 1301 |
| 6 | CITY OF MANILA | Barangay 6 | 1301 |
| 7 | CITY OF MANILA | Barangay 7 | 1301 |
| 8 | CITY OF MANILA | Barangay 8 | 1301 |
| 9 | CITY OF MANILA | Barangay 9 | 1301 |
| 10 | CITY OF MANILA | Barangay 10 | 1301 |
条件是第一个我将从ref_cities获取名称和id。之后,我将在市政专栏中找到该名称。如果找到,它会将我的ref_cities中的id从我的ref_draft中插入到city_code中。
这是我用于更新行的PHP代码。 (即使用codeigniter)
<?php
$findCityName = "SELECT id,name FROM ref_cities";
$resultFindCity = $this->db->query($findCityName);
foreach($resultFindCity->result_array() as $row){
$name = $row['name'];
//$name = 'Manila';
$update = array(
'city_code' => $row['id']
);
$this->db->like('municipality','{$name}');
$this->db->update('ref_draft',$update);
}
?>
答案 0 :(得分:3)
$this->db->like('municipality','{$name}');
应该是
$this->db->like('municipality',"{$name}");
OR
$this->db->like('municipality',$name);
单个引号变量内部被视为字符串,而不是实际变量。将其括在双引号内或不使用任何引号。