在循环迭代期间，2d动态数组的值被破坏

Question

2d动态数组的值在循环迭代期间被破坏，例如在循环决策/迭代16中，所有值都正确显示但是当来到Decision / iteration 26时，阵列位置KillRate 2即使在迭代没有赋值给KillRate数组。如附图所示。

for(int i=0;i<26;i++)
{
    for(int j=0;j<9;j++)
    {
        x[i][j]=0;
        y[i][j]=0;
    }
}
x[0][0]=0;
x[0][1]=.33;
x[0][2]=.75;


x[1][0]=0;
x[1][1]=.33;
x[1][2]=.75;

x[2][0]=0;
x[2][1]=.33;
x[2][2]=.75;

x[3][0]=0;
x[3][1]=.33;
x[3][2]=.75;



    void Display()
{
    int StageValue;
    int DecisionValue;
    double long Minimum;
    TreeNodeType *T;
    cout<<"**********************@@@@@DISPLAY STARTED@@@@**************************************"<<endl;
    for(TreeNodeType *p=Headptr;p!=NULL;p=p->FirstChild)
    {

        KillRate[3][0]=0;
        KillRate[3][1]=.33;
        KillRate[3][2]=.75;


        DecisionValue=-1;
        cout<<"\n\n\n"<<endl;
        for(TreeNodeType *q=p;q!=NULL;q=q->Siblings)
        {
            if(q==Headptr)
            {
                q->PestPopulation=pestpop;
            }
            else
            {

                StageValue=q->stage-1;
                DecisionValue=DecisionValue+1;  
                if(DecisionValue==(noOfDecisions))
                {
                    DecisionValue=0;
                }

                double C1=KillRate[StageValue][DecisionValue];
                double K1=Cost[StageValue][DecisionValue];
                cout<<"Stage Value/Decision Value"<<StageValue<<"/"<<DecisionValue<<endl;
                q->PestPopulation=q->Parent->PestPopulation;
                 long double a=(1 - C1);

                 long double b=(PI)*(q->PestPopulation);
                 long double c=(K1)*(this->area);
                 for(int i=0;i<26;i++)
                 {  

                     for(int j=0;j<9;j++)
                     {
                                 cout<<"KillRate:"<<KillRate[i][j]<<" ";//THIS IS THE PLACE WHERE THROUGH ITERATION ARRAY IS BEING DISPLAYED
                     }
                 cout<<endl;
                 }

                cout<<a<<"*"<<b<<"+"<<c<<endl;
                q->Loss= (a*b)+ c;
                TotalLoss[q->stage-1][q->Decision-1]=q->Loss + q->Parent->Loss;
                q->PestPopulation=(1-C1)*(q->PestPopulation)*(this->growthrate);
                cout<<"Stage= "<<q->stage<<", Decision= "<<q->Decision<<",  PestPop="<<q->PestPopulation<<", Loss ="<<q->Loss<<endl<<endl;  


                if(q->Loss>Minimum)
                {
                    Minimum=q->Loss;
                    T=q->Parent;
                }
            }
        }
    }   
    while(T!=Headptr)
    {

        cout<<"Decision Sequence :"<<T->stage<<" / "<<T->Decision<<endl;
        T=T->Parent;
        DecisionSequence[T->stage]=T->Decision;
        cout<<"Decision Sequence :"<<T->Decision<<" ,\t ";
    }
  cout<<"**********************@@@@@DISPLAY ENDED@@@@**************************************"<<endl;

  }

Answer 1

KillRate = new double*[26]; 
for(int i=0;i<26;i++) { KillRate[i] = new double[9];}

此分配仅分配内存。因此未分配的地址将具有任意值。 c ++解决方案将是：

for(int i=0;i<26;i++){
   for(int j=0;j<9;j++){
      KillRate[i][j] = 0;
   } 
} 

或更快的c解决方案; 使用calloc或memset

Answer 2

这可能是因为内存管理问题我遇到了同样的问题，我通过将每个对象变成指针并通过新的对象* KillRate = new object分配内存来解决这个问题;

希望这可能会有所帮助