Question

我有一个5步注册表单，其中第一步嵌入到主页中。因此，step1是主页的一部分，其余步骤将贯彻执行。我喜欢为step2到step5拥有唯一的URL。基于此我尝试设计URLS但我仍然坚持如何离开第一步成为主页URL（mysite.com），其余的就像mysite.com/signup/step2等。

以前曾是我的单一工作网址

from apps.profile.views.login import SignupWizard, SIGNUP_FORMS
    from apps.profile.forms import MultiPartSignupFormStep1, MultiPartSignupFormStep2, MultiPartSignupFormStep3, MultiPartSignupFormStep4,MultiPartSignupFormStep5

urlpatterns = patterns('apps.profile.views.login',
        url(r'^$', SignupWizard.as_view(SIGNUP_FORMS), name="signup"),
)

这是我现在的代码

from apps.profile.views.login import SignupWizard, SIGNUP_FORMS
from apps.profile.forms import MultiPartSignupFormStep1, MultiPartSignupFormStep2, MultiPartSignupFormStep3, MultiPartSignupFormStep4,MultiPartSignupFormStep5
named_forms = (
    ('step1', MultiPartSignupFormStep1),
    ('step2', MultiPartSignupFormStep2),
    ('step3', MultiPartSignupFormStep3),
    ('step4', MultiPartSignupFormStep4),
    ('step5', MultiPartSignupFormStep5),
)

wizard = SignupWizard.as_view(named_forms)
    #url_name='step1', done_step_name='finished')

urlpatterns = patterns('apps.profile.views.login',
    url(r'^account/signup/(?P<step>.+)/$', wizard),
    #url(r'^account/signup/$', wizard),

)

如何将step1作为主页URL和其余步骤的唯一URL？

Answer 1

也许这会奏效：

from apps.profile.views.login import SignupWizard, SIGNUP_FORMS
from apps.profile.forms import MultiPartSignupFormStep1, MultiPartSignupFormStep2, MultiPartSignupFormStep3, MultiPartSignupFormStep4,MultiPartSignupFormStep5

step1 = (('step1', MultiPartSignupFormStep1),)
other_steps = (
    ('step2', MultiPartSignupFormStep2),
    ('step3', MultiPartSignupFormStep3),
    ('step4', MultiPartSignupFormStep4),
    ('step5', MultiPartSignupFormStep5),
)

wizard_step1 = SignupWizard.as_view(step1, url_name='wizard_step1')
wizard_other_steps = SignupWizard.as_view(other_steps, url_name='wizard_other_steps')

urlpatterns = patterns('apps.profile.views.login',
    url(r'^$', wizard_step1, name='wizard_step1'),
    url(r'^account/signup/(?P<step>.+)/$', wizard_other_steps, name='wizard_other_steps'),
)

Django表单向导独特的URL设计

1 个答案: