返回基于关联表缩小SELECT

Question

我有一个用于从另一个表中提取数据的连接查询：

SELECT [THEME].[NAME], 
       [THEMETYPE].[TYPE] 
FROM   [THEME] 
       LEFT OUTER JOIN [THEMETYPE] 
                    ON [THEME].[THEMETYPEID] = [THEMETYPE].[PK_THEMETYPE] 
WHERE  COALESCE([THEME].[THEMETYPEID], 'null') LIKE '%' 
ORDER  BY CASE 
            WHEN [THEMETYPE].[TYPE] IS NULL THEN 1 
            ELSE 0 
          END, 
          [THEMETYPE].[TYPE] 

如果第3个表值匹配，我需要添加缩小范围的能力：

Where producttheme.productid = variable-paramater-here 
AND producttheme.themeid = theme.pk_theme 

以下是该表的图片：

因此，如果上面选择了1，它将返回所有[主题]。[名称]和关联的[ThemeType]。[Type]其中ThemeId与ProductId = 1

相关联

编辑：更清楚ThemeId是主题表中存在Theme.Name的主键。

Answer 1

这会给你一些想法，请相应地调整列名：

SELECT [Theme].[Name], [ThemeType].[Type] 
FROM [Theme] 
Left Outer Join [ThemeType] 
ON [Theme].[ThemeTypeId] = [ThemeType].[PK_ThemeType]
join ProductTheme PT
on  PT.ProductID=ThemeType.ProductID
WHERE ProductTheme.ProductID = VARIABLE-PARAMATER-HERE AND ProductTheme.ThemeId = Theme.PK_Theme
ORDER BY [ThemeType].[Type]

Answer 2

根据您在添加第3个表之前是否需要WHERE条件，您可以尝试以下两个选项之一：

SELECT * 
FROM   TABLE1 T1 
       LEFT OUTER JOIN TABLE2 T2 
                    ON T1.FIELDA = T2.FIELDA 
       INNER JOIN TABLE3 T3 
               ON T1.FIELDA = T3.FIELDA 
WHERE  T1.FIELDB = 'aaa' 
       AND T3.FIELDC = 12 

或：

SELECT * 
FROM   (SELECT T1.FIELDA, 
               T2.FIELDB 
        FROM   TABLE1 T1 
               LEFT OUTER JOIN TABLE2 T2 
                            ON T1.FIELDA = T2.FIELDA 
        WHERE  T1.FIELDC = 'aaa')T3 
       INNER JOIN TABLE3 T4 
               ON T3.FIELDA = T3.FIELDA 
                  AND T4.FIELDC = 12 

我希望这能为你提供一些工作。

如果您提供一些示例数据，我可以设置一个工作示例。