如何反转行的顺序

时间:2013-07-29 14:10:05

标签: excel vba excel-vba

我尝试编写一个可以反转Excel工作表中行的顺序的宏,但不幸的是我失败了。我甚至不知道如何开始。如果有任何帮助或提示,我将非常感激。

2 个答案:

答案 0 :(得分:4)

选择行并运行此宏:

Sub ReverseList()
    Dim firstRowNum, lastRowNum, thisRowNum, lowerRowNum, length, count As Integer
    Dim showStr As String
    Dim thisCell, lowerCell As Range
    With Selection
        firstRowNum = .Cells(1).Row
        lastRowNum = .Cells(.Cells.count).Row
    End With
    showStr = "Going to reverse rows " & firstRowNum & " through " & lastRowNum
    MsgBox showStr

    showStr = ""
    count = 0
    length = (lastRowNum - firstRowNum) / 2
    For thisRowNum = firstRowNum To firstRowNum + length Step 1
        count = count + 1
        lowerRowNum = (lastRowNum - count) + 1
        Set thisCell = Cells(thisRowNum, 1)
        If thisRowNum <> lowerRowNum Then
            thisCell.Select
            ActiveCell.EntireRow.Cut
            Cells(lowerRowNum, 1).EntireRow.Select
            Selection.Insert
            ActiveCell.EntireRow.Cut
            Cells(thisRowNum, 1).Select
            Selection.Insert
        End If
        showStr = showStr & "Row " & thisRowNum & " swapped with " & lowerRowNum & vbNewLine
    Next
    MsgBox showStr
End Sub

如果您不喜欢通知,请注释掉MsgBox。

答案 1 :(得分:0)

我简化了Wallys代码并更改了它,因此它将行号作为输入参数:

Sub ReverseList(firstRowNum As Integer, lastRowNum As Integer)

  Dim upperRowNum, lowerRowNum, length As Integer

  length = (lastRowNum - firstRowNum - 2) / 2
  For upperRowNum = firstRowNum To firstRowNum + length Step 1
    lowerRowNum = lastRowNum - upperRowNum + firstRowNum

    Cells(upperRowNum, 1).EntireRow.Cut
    Cells(lowerRowNum, 1).EntireRow.Insert
    Cells(lowerRowNum, 1).EntireRow.Cut
    Cells(upperRowNum, 1).EntireRow.Insert
  Next
End Sub

托比