Question

我已经尝试过NSDate，但没有运气。我想要例如14:10和18:30之间的区别。

小时和分钟。

我希望你能帮助我不要那么复杂：）

Answer 1

无需手动计算，请查看NSCalendar。如果您想获得两个日期之间的小时和分钟，请使用以下内容：

NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger unitFlags = NSHourCalendarUnit | NSMinuteCalendarUnit;
NSDateComponents *components = [gregorianCalendar components:unitFlags
                                                    fromDate:firstDate
                                                      toDate:otherDate
                                                     options:0];
[gregorianCalendar release];

您现在拥有NSDateComponents的小时和分钟，可以NSIntegers和[components hour] [components minute]访问它们。这也可以在几天，闰年和其他有趣的东西之间工作几个小时。

Answer 2

这是我的快速解决方案：

NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setDateFormat:@"HH:mm"];
NSDate *date1 = [df dateFromString:@"14:10"];
NSDate *date2 = [df dateFromString:@"18:09"];
NSTimeInterval interval = [date2 timeIntervalSinceDate:date1];
int hours = (int)interval / 3600;             // integer division to get the hours part
int minutes = (interval - (hours*3600)) / 60; // interval minus hours part (in seconds) divided by 60 yields minutes
NSString *timeDiff = [NSString stringWithFormat:@"%d:%02d", hours, minutes];

Answer 3

NSDate类有一个方法timeIntervalSinceDate来完成这个技巧。

NSTimeInterval secondsBetween = [firstDate timeIntervalSinceDate:secondDate];

NSTimeInterval是一个双精度数，表示两次之间的秒数。

Answer 4

NSString *duration = [self calculateDuration:oldTime secondDate:currentTime];

- (NSString *)calculateDuration:(NSDate *)oldTime secondDate:(NSDate *)currentTime
{
    NSDate *date1 = oldTime;
    NSDate *date2 = currentTime;

    NSTimeInterval secondsBetween = [date2 timeIntervalSinceDate:date1];

    int hh = secondsBetween / (60*60);
    double rem = fmod(secondsBetween, (60*60));
    int mm = rem / 60;
    rem = fmod(rem, 60);
    int ss = rem;

    NSString *str = [NSString stringWithFormat:@"%02d:%02d:%02d",hh,mm,ss];

    return str;
}

每天两次之间的时间

4 个答案: