Question

我正在开发需要连接web服务以进行响应的android web应用程序。

我正在使用 kSOAP 进行Web服务调用过程。 [kSOAP是用于约束Java环境（如Applet或J2ME应用程序）的SOAP Web服务客户端库。]

如果我将响应的xml保存到本地目录中，例如。 /mnt/sdcard/appData/config.xml 然后当我询问Web服务请求时，首先它会检查本地文件是否在那里然后将该文件视为响应文件，否则连接到服务器。

此过程缩短了响应时间并提高了应用效率。

是否可以将它（'config.xml'）转换为SOAP对象？怎么样？

考虑我的xml本地文件如下：

config.xml中

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" 

xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 

xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<Response xmlns="http://testuser.com/webservices/response">
<Result>
<SName>Test User</SName>
<UnitDesc>SAMPLE Test </UnitDesc> <RefreshRate>60</RefreshRate>
<Out>
<Definition>
<Code>ABC</Code>
<Description>(Specific)</Description>
<Action>true</Action>
<Despatch>false</Despatch>
</Definition>
<Definition>
<Code>CDE</Code><Description>(Specific)</Description>
<ActionDate>true</ActionDate>
</Definition>
</Out>
<SampleText>
<string>Test XML Parsing</string>
<string>Check how to convert it to SOAP response</string>
<string>Try if you know</string>
</SampleText>
<GeneralData>
<Pair>
<Name>AllowRefresh</Name>
<Value>Y</Value>
</Pair>
<Pair>
<Name>ListOrder</Name>
<Value>ACCENDING</Value>
</Pair>
</GeneralData>
</Result>
</Response>
</soap:Body>
</soap:Envelope>

当前代码如下所示：

final String CONFIGURATION_FILE="config.xml";
File demoDataFile = new File("/mnt/sdcard/appData");
boolean fileAvailable=false;
File[] dataFiles=demoDataFile.listFiles(new FilenameFilter() {
@Override
    public boolean accept(File dir, String filename) {
        return filename.endsWith(".xml");
    }
});


for (File file : dataFiles) {

 if(file.getName().equals(CONFIGURATION_FILE))
 {
    fileAvailable=true;
 }


 }

if(fileAvailable)
    {
        //**What to do?**
    }
else
{

   //Create the envelope
   SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);

    //Put request object into the envelope
    envelope.setOutputSoapObject(request);

    //Set other properties
    envelope.encodingStyle = SoapSerializationEnvelope.XSD;
    envelope.dotNet = true;
    String method="test";

        synchronized (transportLockObject)
        {
            String soapAction = "http://testuser.com/webservices/response/"+method;

            try {
                transport.call(soapAction, envelope);
            } catch (SSLHandshakeException she) {
                she.printStackTrace();
                SecurityService.initSSLSocketFactory(ctx);
                transport.call(soapAction, envelope);             
            }
        }

        //Get the response
        Object response = envelope.getResponse();

        //Check if response is available... if yes parse the response
        if (response != null)
        {
            if (sampleResponse != null)
            {
                sampleResponse.parse(response);
            }
        }
        else 
        {
            // Throw no response exception
            throw new NoResponseException("No response received for " + method + " operation");
        }

}

Answer 1

您可以扩展HttpTransportSE类并覆盖方法call，如下所示：

public void call(String soapAction, SoapEnvelope envelope) throws IOException, XmlPullParserException
{
    if(localFileAvailable)
    {
        InputStream is = new FileInputStream(fileWithXml);
        parseResponse(envelope, is);
        is.close();
    }
    else
    {
        super.call(soapAction, envelope);
    }
}

Answer 2

问题是如何将xml文件转换为SoapObject。那么如何将输入的xml信封放入ksoap2调用中。

实现此目的的方法实际上是在HttpTransportSE类中可用的，即使这不是它的预期用途！

有一个方法“parseResponse”，它接收信封和输入流（您的xml文件）并更新信封输入标题和正文。但聪明的是你可以将它们复制到outHeader和outBody字段中，然后映射字段的所有辛苦工作都会消失。

        @Override
public void call(String soapAction, SoapEnvelope envelope) throws IOException, XmlPullParserException {
    if ( getFileInputStream() != null ){

        parseResponse(envelope, getFileInputStream());
        envelope.bodyOut = envelope.bodyIn;
        envelope.headerOut = envelope.headerIn;
        getFileInputStream().close();
    }

    super.call(soapAction,envelope);

}

如何将本地xml文件转换为org.ksoap2.serialization.SoapObject？

2 个答案: