我有一个集合,其中每个对象都包含用户的详细信息以及用户对特定产品的评论,如下所示
{
"_id" : ObjectId("51efcbc8786df13540e46887"),
"value": {
"UserDetails" : [
[
{
"country" : "CA",
"gender" : "M",
"age" : "18",
"userIdtemp" : ObjectId("51efcbc8786df13540e46887")
}
]
],
"comments" : [
{
"commentId" : ObjectId("51efcc41786df13540e46891"),
"comment" : "Hey, what's up?",
"created" : ISODate("2013-07-24T12:44:49.400Z"),
"productId" : ObjectId("51efcbd4786df13540e4688c"),
"userId" : ObjectId("51efcbc8786df13540e46887")
},
{
"commentId" : ObjectId("51efcc43786df13540e46893"),
"comment" : "Cool",
"created" : ISODate("2013-07-24T12:44:51.004Z"),
"productId" : ObjectId("51efcbd2786df13540e4688b"),
"userId" : ObjectId("51efcbc8786df13540e46887")
}
]
}
}
{
"_id" : ObjectId("51efcbc8786df13540e46888"),
"value" : {
"UserDetails" : [
[
{
"country" : "US",
"gender" : "M",
"age" : "25",
"userIdtemp" : ObjectId("51efcbc8786df13540e46888")
}
]
],
"comments" : [
{
"commentId" : ObjectId("51efcc41786df13540e46892"),
"comment" : "Not much",
"created" : ISODate("2013-07-24T12:44:49.475Z"),
"productId" : ObjectId("51efcbd4786df13540e4688c"),
"userId" : ObjectId("51efcbc8786df13540e46888")
}
]
}
}
{
"_id" : ObjectId("51efcbc8786df13540e46889"),
"value" : {
"UserDetails" : [
{
"country" : "US",
"gender" : "F",
"age" : "13",
"userIdtemp" : ObjectId("51efcbc8786df13540e46889")
}
]
}
}
我必须单独提取注释以及带有key作为productId的userDetails,所以我写了类似下面的地图
mapCommentsFrom = function(){
if("comments" in this.value)
{
for(var idx = 0;idx<this.value.comments.length;idx++){
var key = this.value.comments[idx].productId;
var value = [{
commentId: this.value.comments[idx].commentId,
comment:this.value.comments[idx].comment,
created:this.value.comments[idx].created,
productId:this.value.comments[idx].productId,
userId:this.value.comments[idx].userId,
country:this.value.UserDetails[0][0].country,
gender:this.value.UserDetails[0][0].gender,
age : this.value.UserDetails[0][0].age
}]
}
}
emit(key,value);
}
reduceFrom = function(k,values){
return values;
}
但是哪里的评论数量多于一个,我只得到最后一条评论以及用户详细信息和其他密钥以及值即将为空。像这样的东西
{ "_id" : null, "value" : null }
{
"_id" : ObjectId("51efcbd2786df13540e4688b"),
"value" : [
{
"length" : 2,
"commentId" : ObjectId("51efcc43786df13540e46893"),
"comment" : "Cool",
"created" : ISODate("2013-07-24T12:44:51.004Z"),
"productId" : ObjectId("51efcbd2786df13540e4688b"),
"userId" : ObjectId("51efcbc8786df13540e46887"),
"country" : "CA",
"gender" : "M",
"age" : "18"
}
]
}
{
"_id" : ObjectId("51efcbd4786df13540e4688c"),
"value" : [
{
"length" : 1,
"commentId" : ObjectId("51efcc41786df13540e46892"),
"comment" : "Not much",
"created" : ISODate("2013-07-24T12:44:49.475Z"),
"productId" : ObjectId("51efcbd4786df13540e4688c"),
"userId" : ObjectId("51efcbc8786df13540e46888"),
"country" : "US",
"gender" : "M",
"age" : "25"
}
]
}
有人可以帮我解释一下我错过了什么吗?
提前感谢您的帮助
答案 0 :(得分:0)
由于声誉,我无法添加评论。但是你考虑过使用聚合框架吗?
$unwind
运算符将非常容易地返回一个子文档数组,它比使用map / reduce更快。
我不确定它会完全按照您的要求行事,但可能有所帮助。
看看http://docs.mongodb.org/manual/reference/aggregation/unwind/
答案 1 :(得分:0)
通过远,最简单的方法就是使用聚合框架。聚合框架允许您对数据执行运算符,$match
用于执行查询(如find()
)和其他各种操作。有关详细信息,请参阅:http://docs.mongodb.org/manual/core/aggregation/
聚合框架还有一个$unwind
函数,可以完全按照您的要求执行。你使用它像:
db.collection.aggregate( [
{ $unwind: '$value.comments' },
{ $project: {
_id: '$value.comments.productId',
value: 1
} }
] );
在您的示例文档中,返回:
{
"result" : [
{
"_id" : ObjectId("51efcbd4786df13540e4688c"),
"value" : {
"UserDetails" : [
[
{
"country" : "CA",
"gender" : "M",
"age" : "18",
"userIdtemp" : ObjectId("51efcbc8786df13540e46887")
}
]
],
"comments" : {
"commentId" : ObjectId("51efcc41786df13540e46891"),
"comment" : "Hey, what's up?",
"created" : ISODate("2013-07-24T12:44:49.400Z"),
"productId" : ObjectId("51efcbd4786df13540e4688c"),
"userId" : ObjectId("51efcbc8786df13540e46887")
}
}
},
{
"_id" : ObjectId("51efcbd2786df13540e4688b"),
"value" : {
"UserDetails" : [
[
{
"country" : "CA",
"gender" : "M",
"age" : "18",
"userIdtemp" : ObjectId("51efcbc8786df13540e46887")
}
]
],
"comments" : {
"commentId" : ObjectId("51efcc43786df13540e46893"),
"comment" : "Cool",
"created" : ISODate("2013-07-24T12:44:51.004Z"),
"productId" : ObjectId("51efcbd2786df13540e4688b"),
"userId" : ObjectId("51efcbc8786df13540e46887")
}
}
},
{
"_id" : ObjectId("51efcbd4786df13540e4688c"),
"value" : {
"UserDetails" : [
[
{
"country" : "US",
"gender" : "M",
"age" : "25",
"userIdtemp" : ObjectId("51efcbc8786df13540e46888")
}
]
],
"comments" : {
"commentId" : ObjectId("51efcc41786df13540e46892"),
"comment" : "Not much",
"created" : ISODate("2013-07-24T12:44:49.475Z"),
"productId" : ObjectId("51efcbd4786df13540e4688c"),
"userId" : ObjectId("51efcbc8786df13540e46888")
}
}
}
],
"ok" : 1
}
答案 2 :(得分:0)
因为你没有在map函数中发出它们。 在for循环中移动emit函数。
mapCommentsFrom = function(){
if("comments" in this.value){
for(var idx = 0;idx<this.value.comments.length;idx++){
var key = this.value.comments[idx].productId;
var value = {
commentId: this.value.comments[idx].commentId,
comment:this.value.comments[idx].comment,
created:this.value.comments[idx].created,
productId:this.value.comments[idx].productId,
userId:this.value.comments[idx].userId,
country:this.value.UserDetails[0][0].country,
gender:this.value.UserDetails[0][0].gender,
age : this.value.UserDetails[0][0].age
}
emit(key,value);
}
}
}
然后你可能还需要将reduce函数重写为这样的
reduceFrom = function(k,valueArray){
var returnData = { values : [] } ;
for(var i=0;i<valueArray.length;i++)
returnData.values.push(valueArray[i]);
return returnData;
}