我在dbpre_exer5; // mysql wampserver2.2
中得到了这些表+-----------------------+
| Tables_in_dbpre_exer5 |
+-----------------------+
| tblcourse |
| tblcutoff |
| tblgrades |
| tblstud |
| tblsub |
+-----------------------+
现在,我只想问一下考虑到存储过程的使用,我将如何获得这些输出。 输出是:
+---------+----------------+---------------+-------+
| Gender | With Failure | W/out Failure | Total |
+---------+----------------+---------------+-------+
| Male | 1 | 1 | 2 |
| Female | 2 | 1 | 3 |
+---------+----------------+---------------+-------+
顺便说一下,这里是enter code here
;
**
mysql> select * from tblcourse;
+-----------+------------------------+
| course_id | course_name |
+-----------+------------------------+
| 1 | Information Technology |
| 2 | Computer Science |
+-----------+------------------------+
2 rows in set (0.00 sec)
mysql> select * from tblgrades;
+---------+--------+-------+
| stud_id | sub_id | grade |
+---------+--------+-------+
| 1 | 1 | 80 |
| 1 | 2 | 78 |
| 2 | 2 | 75 |
| 2 | 3 | 84 |
| 3 | 1 | 81 |
| 3 | 3 | 90 |
| 4 | 1 | 74 |
| 4 | 2 | 77 |
| 5 | 2 | 76 |
| 5 | 3 | 81 |
+---------+--------+-------+
10 rows in set (0.00 sec)
mysql> select * from tblcourse;
+-----------+------------------------+
| course_id | course_name |
+-----------+------------------------+
| 1 | Information Technology |
| 2 | Computer Science |
+-----------+------------------------+
2 rows in set (0.00 sec)
mysql> select * from tblcutoff;
+-----------+
| passgrade |
+-----------+
| 78 |
+-----------+
1 row in set (0.00 sec)
mysql> select * from tblgrades;
+---------+--------+-------+
| stud_id | sub_id | grade |
+---------+--------+-------+
| 1 | 1 | 80 |
| 1 | 2 | 78 |
| 2 | 2 | 75 |
| 2 | 3 | 84 |
| 3 | 1 | 81 |
| 3 | 3 | 90 |
| 4 | 1 | 74 |
| 4 | 2 | 77 |
| 5 | 2 | 76 |
| 5 | 3 | 81 |
+---------+--------+-------+
10 rows in set (0.00 sec)
mysql> select * from tblstud;
+---------+-------------------+--------+-----------+
| stud_id | stud_name | gender | course_id |
+---------+-------------------+--------+-----------+
| 1 | Angelina Jolie | F | 1 |
| 2 | Jennifer Garner | F | 1 |
| 3 | Liam Neeson | M | 2 |
| 4 | Paul Walker | M | 2 |
| 5 | Jennifer Lawrence | F | 2 |
+---------+-------------------+--------+-----------+
5 rows in set (0.00 sec)
mysql> select * from tblsub;
+--------+------------+
| sub_id | sub_name |
+--------+------------+
| 1 | Math 1 |
| 2 | English 1 |
| 3 | Filipino 1 |
+--------+------------+
3 rows in set (0.00 sec)
mysql>
**
我的第一个问题是在性别下得到“男性”和“女性”的结果。 任何帮助?非常感谢。
答案 0 :(得分:0)
答案 1 :(得分:0)
<强>已更新强>
SELECT gender,
SUM(failure) `With failure`,
COUNT(*) - SUM(failure) `Without failure`,
COUNT(*) total
FROM
(
SELECT s.stud_id,
CASE WHEN s.gender = 'M' THEN 'Male' ELSE 'Female' END gender,
MAX(CASE WHEN g.grade < c.passgrade THEN 1 ELSE 0 END) failure
FROM tblgrades g JOIN tblstud s
ON g.stud_id = s.stud_id CROSS JOIN tblcutoff c
GROUP BY s.stud_id
) q
GROUP BY gender
示例输出:
| GENDER | WITH FAILURE | WITHOUT FAILURE | TOTAL | --------------------------------------------------- | Female | 2 | 1 | 3 | | Male | 1 | 1 | 2 |
这是 SQLFiddle 演示